Studio_2sol - -5 : 11011 12: 01100 g)-3-7 = -10 11101...

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1) a) In 6 bit 2's complement, we can represent numbers from -32 to +31 (both inclusive) hence (b), (d), (f) cannot be represented. b) 0000 = 0 0001 = 1 0010 = 2 0100 = 4 1000 = -8 1100 = -4 1110 = -2 1111 = -1 c) taking two's complement is the same as negating the numbers. the 2's complements of the numbers are 0000 1111 1110 1100 1000 0100 0010 0001 d) the decimal values for the binary interpretation of the numbers are: 0, 1, 2, 4, 8, 12, 14, 15 e) hex representation 0 1 2 4 8 C E F f) -3: 11101 -7: 11001 -1: 11111 1 : 00001 5 : 00101 -12: 10100
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Unformatted text preview: -5 : 11011 12: 01100 g)-3-7 = -10 11101 +11001-------10110 (-10)-1+1 = 0 11111 +00001-------00000 5-12 = -7 00101 +10100--------11001 (-7)-5+12 = 7 11011 +01100-------00111 (7) h) 10011 10111 10001 00001 00101 11100 10101 01100 2) Straightforward gate implementation in LogicWorks 4) It is seen that B and D have identical truth tables. X Y Z | A B C D 0 0 0 | 1 1 0 1 0 0 1 | 1 1 1 1 0 1 0 | 1 0 0 0 1 0 0 | 1 0 0 0 1 1 0 | 0 0 0 0 1 0 1 | 1 1 0 1 0 1 1 | 1 0 1 0 1 1 1 | 0 1 0 1...
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Studio_2sol - -5 : 11011 12: 01100 g)-3-7 = -10 11101...

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