105Stoichiometry - elevated temperatures to yield 0.692 g...

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Lesson 5 Empirical and molecular formulae The empirical formula gives the relative number of atoms in a molecule Different substances can have the same empirical formula.
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Lesson 5 Example 1 An oxide of antimony (Sb) is found to contain 24.73% of oxygen by weight. What is its empirical formula?
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Lesson 5 Example 2 Fifty mg of a compound used as dental cement is broken down into its constituent elements and gives 16.58 mg of oxygen, 8.02 mg of phosphorus, and 25.4 mg of zinc. Determine the empirical formula of this compound.
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Lesson 5 Example 3 A 0.578 g sample of pure tin (Sn) is treated with gaseous fluorine until the weight of the resulting compound is constant at a value of 0.944 g. What is the empirical formula of the compound formed during the reaction?
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Lesson 5 Example 4 A sample of 1.0 g of a compound containing carbon and hydrogen reacts with oxygen at
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Unformatted text preview: elevated temperatures to yield 0.692 g of water and 3.381 g of carbon dioxide. What is the empirical formula of the compound? Lesson 5 Using gas densities to calculate molar masses of gases • At standard temperature and pressure = L g : V m ρ mol L 4 . 22 = = mol g mol L L g : mol L 4 . 22 M Lesson 5 Example 4 When 0.21 g of a compound containing only hydrogen and carbon is burned, 0.66 g of Lesson 5 Example 5 A 0.596 g sample of a gaseous compound Lesson 5 Suggested readings 3.1 Types of Chemical Compounds and Their Formulas Lesson 5 Summary • Substances; chemical formulae • Concept of a mole of a substance • Chemical equations • Stoichiometric calculations • Limiting reactants and percentage yields • Empirical and molecular formulae...
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This note was uploaded on 04/17/2008 for the course CHEMISTRY CHE102 taught by Professor Grove during the Fall '06 term at Waterloo.

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105Stoichiometry - elevated temperatures to yield 0.692 g...

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