Homework 3 Part 2

Homework 3 Part 2 - Homework #3 "Sum of Dice and Black...

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Click to edit Master subtitle style 5/11/09 Homework #3 “Sum of Dice and Black Beans” Group 3 Cesar McFarlin Adam Davidson Adam Schatz TJ Murphy
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5/11/09 Problem Statement Use the class data collected at the start of the semester Derive the Confidence Intervals at 90%, 95%, and 99% for sum of dice. Also, derive it for the proportion in the case of the black beans sample.
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5/11/09 Confident Interval (C.I.)of a sample X ± σ x Z α/2 & X ± (s/ √n) x Z α/2 X = sample mean n = sample size Sx = sample Standard Deviation Z α/2 = z-value with an area of /2 to its right (as seen on the Cumulative Normal Probability table)
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5/11/09 90% Confidence Interval (C.I) From the table, the value of Z in a 90% Confidence interval is 1.65 Z α/2 = Z .5 = 1.65 % of C.I 1 - α α α/2 90% 0.90 0.1 0.5
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Sum of Dice Given information: X = 7.561 Variable N SE Mean StDe v Minimu m Q1 Media n Q3 Maximu m Sum of Dice 4 1 7.561 0.33 9 2.169 3.00 0 7.000 9.00 0 11.000 X ± (s/ √n) x Z
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Homework 3 Part 2 - Homework #3 "Sum of Dice and Black...

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