ch05_p52 65 - system = 24.0 kg This yields an acceleration...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
52. First we analyze the entire system with “clockwise” motion considered positive (that is, downward is positive for block C , rightward is positive for block B , and upward is positive for block A ): m C g m A g = Ma (where M = mass of the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: system = 24.0 kg). This yields an acceleration of a = g ( m C − m A )/ M = 1.63 m/s 2 . Next we analyze the forces just on block C : m C g – T = m C a . Thus the tension is T = m C g (2 m A + m B )/ M = 81.7 N....
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online