ch09_p28 30 - t = 4 s to be (30 kg . m/s)i ^ . (b)...

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28. (a) By the impulse-momentum theorem (Eq. 9-31) the change in momentum must equal the “area” under the F ( t ) curve. Using the facts that the area of a triangle is 1 2 (base)(height), and that of a rectangle is (height)(width), we find the momentum at
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Unformatted text preview: t = 4 s to be (30 kg . m/s)i ^ . (b) Similarly (but keeping in mind that areas beneath the axis are counted negatively) we find the momentum at t = 7 s is (38 kg . m/s)i ^ . (c) At t = 9 s, we obtain p → = (6.0 m/s)i ^ ....
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This test prep was uploaded on 04/22/2008 for the course PHYSICS 1100 taught by Professor Grassers during the Spring '08 term at Rensselaer Polytechnic Institute.

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