{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ch09_p21 22 - p o is 6.0 kg·m/s Thus cos θ o = p x p o ...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
21. We infer from the graph that the horizontal component of momentum p x is 4.0 kg·m/s. Also, its initial magnitude of momentum
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: p o is 6.0 kg·m/s. Thus, cos θ o = p x p o ¡ o = 48 ° ....
View Full Document

{[ snackBarMessage ]}