Ch09_p21 22 - p o is 6.0 kg·m/s Thus cos θ o = p x p o o = 48 °.

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21. We infer from the graph that the horizontal component of momentum p x is 4.0 kg·m/s. Also, its initial magnitude of momentum
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Unformatted text preview: p o is 6.0 kg·m/s. Thus, cos θ o = p x p o ¡ o = 48 ° ....
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This test prep was uploaded on 04/22/2008 for the course PHYSICS 1100 taught by Professor Grassers during the Spring '08 term at Rensselaer Polytechnic Institute.

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