{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# hws04 - 4(7)Design a combinational circuit that takes 2...

This preview shows pages 1–2. Sign up to view the full content.

COCO 2610 Solution to Homework 4 Total score: 2~points 1) (~ith 2' each) 4.10 (c), (d),~ (c) F = A'B'C'D+A'B'CD'+A'BC'D+A'BCD' F = IIA,B,c,D(0,3,4,7,8,9,10,11,12,13,14,15) = (A+B+C+D) (A+B+C'+D') (A+B'+C+D) (A+B'+C'+D') (A'+B+C+D) (A'+B+C+D') (A'+B+C'+D) (A'+B+C'+D') (A'+B'+C+D) (A'+B'+C+D') (A'+B'+C'+D) (A'+B'+C'+D (d) F = (M+N+P) (M+N+P') (M+N'+P') (M'+N'+P) (M'+N'+P') F =~ ( 2 4 5 ) = M'NP'+MN'P'+MN'P M,N,P " "1~\-~;"(NY')~7+7')+VZ'(X-+~)- } "n:z-,.:>.u.Y--'-Z-=t"X->YZ-2..H~' , ~YL'TX'y"Z ,.-- ,~:zcv,l;2-;3~ ~t4:5J1 ~~..1+-Y-r.P1(-X..l..J::Y--I--2-"'ltX'TY-'-tZ.2.. 2) (8' with 2' each) 4-13 (c)-(f) (c) F = ~w,xy(2,6,7) = XY'+WX ~I (e) F =~A,B,c,D(0,2,3,4,5,6,8,10,11,12,14) = D'+B'C+A'BC' (f) F = BC'D'+A'C'D+BCD+ABC (this answer may vary due to different m( combination) 1 1 3) (4' with 2' each) 4-16 (a) and (f) (a) F = A'C'+B'C'+A'B'

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
9Wl ~1 ~ (f) F =LA,B,c,o(O,2,8,10,11,15) = ACD+B'D'
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 4) (7')Design a combinational circuit that takes 2 inputs and outputs its two's complement. a) specify the input and output, how many outputs? (2') b) produce the truth table (2') c) give the canonical sum for each output (2') d) minimize each output expression if necessary using K-map (l') a) Since the input must be 2-bit signed number represented in two's complement. The input therefore ranges from -2 to 1. To represent the two's complement (or negative) of the input, we need 3 bits output (since 2 can not be represented by 2-bit in two's complement). The output number ranges from 2 to -1 to correspond to the input number range. b) c) A = LX,y(l) = X'Y B = Lx,y(l,2) = X'Y+XY' C = Lx,y(l,3) = X'Y+XY d) A=X'Y, B=X'Y+XY', C=Y x y A B C 1 1 1 1 1 1 1 1 1...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern