# hwsol1 - 4 8 145 2 144 11=B 3(1pt for each part 2.7(a 2.7(c...

This preview shows pages 1–2. Sign up to view the full content.

Solution to ECSE 2610 Homework Set 1 For problem in items 2 to 4 , process should be shown to get full credits. 1. (1.6) (1 pt) Input Output ------------------------------- 0 0 0 0 1 1 1 0 1 1 1 1 (2 pts) The same function is performed by a single 2-input OR gate. (2 pts) 2. (1 pt for each part) 2.1(a) 110 2 =6 16 , 1011 2 =B 16 , so 1101011 2 =6B 16 2.1(f) F 16 =1111 2 , 3 16 =0011 2 , A 16 =1010 2 , 5 16 =0101 2 , so F3A5 16 =1111001110100101 2 2.3(c) A 16 =1010 2 , B 16 =1011 2 , C 16 =1100 2 , D 16 =1101 2 , so ABCD 16 =1010101111001101 2 1 010 101 111 001 101 2 1 2 5 7 1 5 8 so ABCD 16 =125715 8 2.5(a) 1101011 2 =1x2 6 +1x2 5 +1x2 3 +1x2 1 +1x2 0 =107 10 2.5(f) F3A5 16 =15x16 3 +3x16 2 +10x16 1 +5x16 0 =62373 10 2.6(a) 125 10 =1111101 2 62 31 15 7 3 1 2 )125 2 ) 62 2 )31 2 ) 15 2 ) 7 2 ) 3 12 62 2 14 6 2 5 0 11 1 1 1 4 10 1 1 2.6(f) 23851 10 =5D2B 16 1490 93 5 16 ) 23851 16 ) 1490 16 ) 93 16 144

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document