Sample_Final1_Ans - 9»% Final Exam Last name of student...

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Unformatted text preview: 9»% Final Exam Last name of student Student ID number \~ 60Lu1”: OMS: First name of student Email address x».va ,..__.»......._....,WM._ , Exam Rules: This is a 2 hour and 50 minutes exam The syllabus includes all material covered during this semester This is an Open Book and Notes Exam You are not allowed to consult any other student You may NOT use a calculator, laptop, palmtop, PDA, or such other computer If you need more space, continue on the back sides of pages, but make sure to indicate a continuation nun.- I oints Boolean Building Word Reverse Stacks & Interrupts Bus Interfacing Blocks Problem En ineerin ; Subroutines ECSE-2‘610 Computer Components and Operations, Fall 2000 Page 1 of 15 p0} »\‘V ? ,Oggm 1. (20 points) Arithmetic/Combinatorial Logic, K-Maps, Boolean Theorem Proving. a. (3 points) Consider the following un-minimized circuit for function F. Use Boolean algebra to minimize the function F, and then draw the circuit corresponding to the minimized circuit implementing the same function, F. X [ F Y Z P“- L><+\f)-\/Z "D “" : (mu) 4 ~12. A W” b. (3 points) Using Boolean algebra theorems, show that x +(; + EXx + ; + E) = x +yz ’DL 4: Y» ’5‘}? \ + (5C deg-iv“: )é s; a + a: 3 M We k 'DL + (x+&\,32 ")t {1; 4 i9? a» 2 i. a a: «min e)» l \P“ c. (2 points) Consider the function ;(A,B,C,D) = Z m(0,2,4,5,6,8,9,10,13). Rewrite the expression in canonical Maxterm form. '\ “W l.‘ ‘ g 3,, "’- Ww ~, w r? i’ i1 i a”; C 4.- 3 ( A A (a e Z a '53 y A 443% it ‘5: it, if; r’ X x a t3? a i ,2: ,5 I E 4' f: .x ‘ \ i” ECSE-2610 Computer Components and Operations, Fall 2000 Page 2 of 15 d. (5 points) Consider the function f(A,B,C,D) = Z m(0,2,4,5,6,8,9,10,l3). Use the following K- map to minimize the function and write the result in SOP form. e. (3 points) Does the above function have a static l-hazard ? If so, use the K-map to identify terms you need to add to the function to remove the hazard. Write the SOP form of the revised function below. An extra K-map template is given below for your convenience. AB CD 00 01 11 10 axis ? ~-é.~7.jca. t 0% OM ‘m’ficfirxegk 1 Q. ECSE-2610 Computer Components and Operations, Fall 2000 Page 3 of 15 V/ f. (4 points) Explain briefly, but precisely (in terms of timing) why the use of generates (Gi) and propagates (Pi) in the form of a carry look ahead unit speeds up the multi—bit addition process as compared to an equivalent ripple carry adder. A carry look-ahead diagram is given below for your reference. 0 i Q a W DJ 49A.) A[7-4] B[7-4] A[3-O] BIS-0] 4-bit Adder 4-bit Adder “\h coo» C y P\D“ l“ p o m \\ e} o x 44m C Q 3 Q > \Pcra.4\ a) um COWPML CH. Cv,C.1 , C\Q M ,hvc @S' g; Campwcwoj I U; €h¥1YQ CO’O‘HHO" Camfflehfi Q mph» my} Oo’cimQ SJoQ-Lhol" Cryploil" pom/Lida,“ so H am.“ mm -— 4x11 : \g pm» ‘/ g p V T. ___ Y P 1 z \/‘6 ECSE-2610 Computer Components and Operations, Fall 2000 Page 4 of 15 2. (10 points) Combinational and Sequential Building Blocks JPJ 0 Design a sequence detector with a single input x, and a single 2 using a shift register, a multiplexor, and basic gates (AND/OR/NOT). This circuit should produce an output of “1” whenever any one of the following 3—bit patterns are detected in the input bit sequence: 0 5 5r CBA=111, 110,100, 000 Indicate your answer by wiring the TTL chips shown below (data sheets are attached). The input bit sequence x is shifted right into the register. The parallel outputs of the shift register are to be tested for the desired bit patterns using the multiplexor. '3'. ix 5 f, c i, \ “‘ .. i pic . ; 74Ls1945 l 0 fi31 3 g’ l Iii—r so [L DSL ‘ — P3 Q3 3 , o — P2 02 i * P1 0‘ ‘ 74L8251 fl P0 00 i X Dsn 1 .J’LJL 5» CP | 1 AM? ‘ A 6? :> s .._ 3 W. WM: ’ yo 'Ql’vg Cs OW‘QQCL/ gee i "3:0,? is Waifififl {1 c; . “IL: (L h o r give {3 will; Pam: oi M 100 ECSE~2610 Computer Components and Operations, Fall 2000 Page 5 of 15 3. (10 points) Word Problem Sequential Circuit Synthesis ‘ , 0 Draw the Mealy state diagram for a sequence recognizer with a single input x, and a single z . It produces an output of 2 =1 whenever the sequence 0101 is detected, and 0 at all other times. For example: ‘ Input: x ...0 o 1 o 1 o 1... Output: 2 ...0000101... Your state diagram should not have more than four states. I Vo’ Cos: «ear gram; g V35, a“ Wter <- 2 Pk; verm— z cow act WM” *3“ " x Game: ’7". , Agixrggn \ $ 6% “AL Mar n (e, 0,—3\—-—>0"“‘>\ ECSE-2610 Computer Components and Operations, Fall 2000 Page 6 of 15 vaiUQ/z 4. (15 points) Reverse Engineering Your goal is to reverse engineer the following mystery Mealy machine using the functional analysis method. The parts of this question will help you do this in steps. \ a. ( point) What are the input variables, state variables and output variables of this circuit ? e: l/P ' : gd‘oh W1 [NR 3 Outtrwtzz 1 flfl fl (2 points) Fill up the following tables for the T- and D- flip flops and write out the ., L ((3 m @0966} l' 2 l? or“) Characteristic equation (Q+ in terms of Q and T (or D)) in each case. c. (6 points) Using the characteristic equations above, write equations for the outputs and next states in terms of the inputs and previous states. Substitute equations for the inputs to the T and D flip flops. (For example, the input to the D flip flop is \A, which will be substituted into its characteristic equation to get the equation for the output B+) / BC1+K) z= Lax—fl). VENUE == 18+ tel) = w = LE» cm @A Ca) ems m 3+: 7%— (27 gxmpflikg'” ECSE-2610 Computer Components and Operations, Fall 2000 Page 7 of 15 d. (2 points) Fill up the next-state (state transition) table and output table below based upon the above equations. {8 , a 4‘ . \ 5 r, ' ,Wg, ...... W ‘ log/(1 0 WW) ,gwaam-7 CO “55 ‘s I. Q “L w M! ' {#6206} _ .‘1 g a, i W V ,. 2r 5 x éM We“? M #2 ‘ § , i ‘ (" Many“: a” ’ ,’ in e. (3 points) Draw the state machine corresponding to the above state transition table. Remember that this is a Mealy Machine with 4 states (corresponding to the bit combinations of A and B, the state bits). ' 1/0 0,!' cowe‘” in . . i- I; .331?“ J“ .1 \ ’_ (“a W) " ” 0/0 mi 3 ~ <70” WW 6% v"- 1— 7 . 5 ' iv“ xv ( " t k c) .‘r a G W ‘ 50 i A , $16.0}? / ,A) 59 ECSE-2610 Computer Components and Operations, Fall 2000 . Page 8 of 15 00“ (‘J( 5. (15 points) Stacks, conditional branches, Assembler directives a. (5 points) Indicate the effect of the following sequence of assembler directives by filling up the tables provided below. The tables may have more boxes than you need, so write XX in all extra spaces. ORG scooo , ALPHA ZMB $El BETA EQU $02 GAMMA FCC ’Hi’ DELTA EQU * + $OA END Address [ Value 4 E 3 L000 - 4 (0 t; 0 Q t ‘ l—(’ $ Lo 1—: I ‘ 7 ’ S_ymbol +__ Value m__ALPHA $L000 i - E: T A i {29. 3 M it c mu . ——*7 \DtLTn “ $(DEED . . j; Mme. ,\ »* l b. (5 points) The initial contents of the stack, and value of the stack pointer are given below: SP = $C256 Write down the new values of the above locations after the following instructions have been executed. PULA s PULB A EORA¢$0A PSHA- DECA RORA PSHA ABA PSHA PSHB *QNCW SP = $ ECSE—2610 Computer Components and Operations, Fall 2000 CQSH /alP"' Initial Stack_ Contents L_______— Memory Contents Address c250 "—SIC C251 $42 C252 $91 _C253 ____$AB C254 , $33 1 C255 $29 :~ C256 , V $11 # '— C257 , . $3C '7 1 - C258, $12 at: C251 $99 ' CZSCA $88 C2593 $A2 Page 9 of 15 _ New Stack Contents Memory Address Contents C250 3. ( L ‘ C251 ‘3 [1 L C252 ‘ 1, q . i c254 51> 33 E C256 5 2.6 3 P §c257 w stm Wav- , \Pr ‘ C258 <5 31‘ ‘ €257 is aa , €255 e. g 2 LGZéE. $Ix1 c. (2 points) The following instruction sequence for comparing two numbers is executed on a 68HC1 1 microcomputer: NUMl EQU $23 NUM2 EQU $87 ORG $COOO LDAA #NUMl CMPA #NUMZ If you were using signed arithmetic, you would conclude that (check the items that apply): [/1 NUM1>NUM2 ,9 lama}? [ ] NUM1=NUM2 [ ] NUM1<NUM2 d. (1 point) What is the value of the overflow bit after the CMPA instruction is executed? a, l’" a v. , m a x r y e. (2 points) For the above program fragment, add suitable instruction(s) following the CMPA instruction that implements the following logic: “if(NUMl 2 NUM2) go to $D000,” assuming that NUMl and NUM2 are signed numbers. NUMl EQU $23 NUM2 EQU $87 ORG $cooo LDAA #NUM1 CMPA #NUM2 M «Mme ] P 9 WW. 7; y {,3 if 3m? $0000 NEXT: ECSE-2610 Computer Components and Operations, Fall 2000 Page 10 of 15 6. (15 points) A question about interrupts A digital voting machine is sketched below. C] The left-most column consists of four binary switches, one for each candidate. CI The middle column consists of a push-button switch that produces a falling edge when pressed. a The right-most column consists of two lamps. The voter is asked to select exactly one candidate, and then press the VOTE push-button. If the voter selects exactly one candidate, the “Accepted” lamp is turned ON, and the “Try Again” lamp is turned OFF. If more than one candidate is selected, or if no candidate is selected, the “Try Again” lamp is turned ON, and the “Accepted” lamp is turned OFF. © Candidate 1 © Candidate 2 © 1‘ © Candidate 3 VOTE © Candidate 4 The above switches and lamps are connected to a 68HC1 l micro-controller in the following manner: Candidate 1 PORTC, bit 0 Candidate 2 PORTC, bit 1 Candidate 3 - PORTC, bit 2 Candidate 4 PORTC, bit 3 VOTE ush-button with fallin ede res onse STRA line “Acce ted” lam PORTC, bit 5 “T A ain” lam PORTC, bit 6 On the next page is a partial interrupt-based program for implementing the voting machine. Complete this program so that it performs the task described above. ECSE-2V610 Computer Components and Operations, Fall 2000 Page 11 of 15 * Main Program PIOC EQU PORTC EQU DDRC EQU PORTCL EQU VECLOC EQU JMPOP EQU IOPAT EQU CTRPATl EQU CTRPAT2 EQU $K.ooa. $ [(303 LLJEQ”I $ 1 oo§’ $ggoEE $ 1L f/Auwooo 00H; 0( $‘To for PIOC register, STAI disabled %D'O° 00“; for PIOC register, STAI enabled * Data Section - setup stack space and initial Stack Pointer ORG $D000 STACK RMB INITSP ORG $C000 'AH c RFA SETUPINT LDS LDAA STAA PIOC ( (W LDAA M STAA DDRC CLR PORTC *setup interrupt vector in Buffalo jump table. LDAA #JMPOP STAA VECLOC LDX #ISRIRQ STX VECLOC+1 *clear status of peripheral or subsystem that could cause an immediate LDA [A PQQT L interrupt. LQAA [WERL ‘ a * Enable Interrupt in peripheral or subsystem 1.32EA £18 :2, saw 010; * Enable Interrupts globally * Jump to main program JMP MAIN ‘ BRA CJ_I MAIN MAIN Ipb. J ECSE-2610 Computer Components and Operations, Fall 2000 PagelZoflS * Interrupt Service Routine ISRIRQ LDX #PIOC BRCLR 0,): 95 \000 OOOQ RTIIRQ -—-o 1 LDAA 7 0c a \ Lb A 'Ponfict A OI I A) ‘ E EC“) 1, a CMP if 7—D { E (20 L. c it ~13 ‘ » ' OVAL, : n?“ 4‘30 3"“) \ Ba? EQUA L QmUAL‘ LDAA’ 7-0‘00000 f; $\ A PORTC, TMP Ilt' 117162 RTIIRQ RTI ECSE-2610 Computer Components and Operations, Fall 2000 ‘ ‘ Page 13 of 15 i\ M t... “'73 r7 i9 7. (10 points) Bus Interfacing It is desired to interface a fiZ-kilobyte static RAM device to a 68HC11 micro—controller chip (please see the diagram on the next page), in the address range starting at $8000. First answer the following questions, and then complete the diagram on the next page as indicated. a. (1 point) What logic values should the MODA and MODB pins be set to? W,,r.4 mg. more: M09825 1 ' o b. (2 points) Write down the address bit pattern that you must detect on the bus. Indicate your answer b writin a 0/ l/X below: . a r y g B i (3.3?“ W *1 fig ’ c. (7 point) For each of the following control signals, write down a Boolean function whose inputs are the signals on the 68HC11 bus (AS, E, R / W , A15 — A8, AD7 # ADO), and other signals that you find necessary, and whose output is the control signal indicated below. ‘( M i a \ filiAOOftheSRAM Iat- Av “’0” ‘5 was Qw’Qo at #8373 \ AlgoEChisalefid, aw \ fiofSRAMchip g "m" "‘ "A \ 3:100 ofthe SRAM AD7 ’ Ava \ oftheSRAM .73 .E 3 R/W +g d. (5 point) Using only AND/OR/NOT gates, complete the diagram on the following page to perform the above memory interfacing task. 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Sample_Final1_Ans - 9»% Final Exam Last name of student...

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