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ME200_Lec3_1.7_2.2_B

ME200_Lec3_1.7_2.2_B - Melting point of ice −459.67 °F...

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13 of 47 K = (°F + 459.67) / 1.8 Kelvin Fahrenheit °F = (K × 1.8) − 459.67 Fahrenheit Kelvin K = °R / 1.8 Kelvin Rankine °R = K × 1.8 Rankine Kelvin K = °C + 273.15 Kelvin Celsius °C = K − 273.15 Celsius Kelvin Formula To From
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14 of 47 211.9710 °F 99.9839 °C 373.1339 K Water’s boiling point 32.018 °F 0.01 °C 273.16 K Water’s triple point 32 °F 0 °C 273.15 K
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Unformatted text preview: Melting point of ice −459.67 °F −273.15 °C 0 K Absolute zero Fahrenheit Celsius Kelvin 15 of 47 16 of 47 17 of 47 18 of 47 19 of 47 20 of 47 21 of 47 22 of 47 23 of 47 24 of 47 25 of 47 26 of 47 27 of 47 28 of 47 29 of 47 30 of 47 31 of 47 32 of 47 33 of 47 34 of 47 35 of 47 36 of 47 37 of 47 38 of 47 39 of 47 40 of 47 41 of 47 42 of 47 43 of 47 44 of 47 45 of 47 46 of 47...
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