Name:Thursday section time:Student ID:Math 20F - Linear Algebra - Spring 2003Quiz #3 — May1(Do not discuss the quiz with students who haven’t taken it yet – until 8:00pm.)You must show your work in order to get credit for a problem.Label your answers clearly.Letu1=101,u2=124,u3=421, andu4=121,1.Isu1,u2,u3a spanning set forR3? Explain why or why not.2.Isu1,u2,u3a basis forR3? Explain why or why not.3.Isu1,u2,u3,u4a spanning set forR3? Explain why or why not.4.Isu1,u2,u3,u4a basis forR3? Explain why or why not.ANSWERS:1. Yes, it is a spanning set. To prove this, you may do one of the following:(a) Form the matrixA=(u1u2u3), putAin row echelon form andnote that the row echelon form does not have any row of all zeros. Or,(b) Form
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This note was uploaded on 04/23/2008 for the course MATH 20F taught by Professor Buss during the Spring '03 term at UCSD.