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Unformatted text preview: 1 + 3 x 2 3 x 12 x 2 = 121 3 32 x 1 x 2 . To solve T ( x ) = 1 4 9 , reduce the augmented matrix, 1211 3 4 32 9 R 2 + R 1 ,R 33 R 1 121 1 3 4 12 R 34 R 2 121 1 3 R 1 +2 R 2 1 5 1 3 . Therefore, x = 5 3 . 1...
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 Fall '06
 Sze
 Math

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