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ph132s04_hw9 - PH 132 SPRING 2004‘ HOMEWORK 9 Assigned...

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Unformatted text preview: PH 132 SPRING 2004‘ HOMEWORK # 9 - : Assigned: 03/08/04 ' v .fl FIND Swan THAT .3 VANISH‘ES AT P. IBII: /Bm": “é“ B;0N€qwm =31:— f1“. = fl". (D‘REC'T’ON ‘5 fling 1-17??? can 0F “PACaE‘ leacrram {5. mm W455" 4: “— HAG- snout—b- Eé 554m?» (A‘m'NCrz Bra'r-SAuR-x- AM. mum-FM 0? Ag; —: 7T :1: LW “)6 50 SHSETS 12 142 100 SHEETS 22-144 200 SHEETS 22-14] 0 _ ammo k "I -' Bi-ot—Szivairt'l‘zlaw to'c'alcuiate the magnetic field E at C. 'eld B I \ . . center of the semicircular arcs AD and H! in Fig. -HJ in . - twin arcs. of radii R2 and R. , respectively, form pan . form ' - - .. it ADJHA carrying current 1'. m ds 1-0 ' -———- fird:[email protected]'MC (a) 5o/u‘b’on Bfo+' SavaH- Law 5a», Hie solufi'm 1‘0 CH 30-le The Segments AH and $0 do mv‘ 60%;ka “ft? 4476 ”761176152 fi'e/d 611‘ Pom+ C. Ea!‘ Poi/l7" C. CS due 40' mg 'I‘wo arcs. 05mg #16 genera] reset/f {Sr 62 semiia'rmhfarc defllv'djh CH 30—HP: : A23: ' 8 4R The .ouwler arc 3M5 B; “5% Q - Use #:e rig/if 1452er ad: in ' 2' fiiwl/ze firm/52:5 {5r Era-ml 1’er ihner arc, {mg 5’: --/(o:‘ “‘ —-- b B 5 ' we, 7* “’1- A25 ~ .1." A _ B [4R2 ‘12:?le " Ndc: A72 PR, ,50 ijfomfs :h 74w “4': ercfibn. 50 SHE! T5 22-142 100 SHEETS 22444 200 SHEETS 22-14] H50— 10 P . - _L ' . - . . a sac gh 5e. 6 of . m m 3c» mm”. Cgl'uen .- figure. (a, c, L, a) 34 carries current i. What mag- ' nelic field B is produced at the center C of the semicircle by mom of mdius R. and (c) the en- - Itire wire? EM, 405 9 cm: fbsfrm‘ + Segmem's _ b) B @ C due (a Semi-drde "‘ ' a) BM dufibm .5, fitdé‘x? ‘ 830+ ‘Samrf Law 61) d6 ‘~‘ 4;; 1ras where d? point {n+he dl‘reah'on 04 4M carrem‘. [3+3 "BMW?“- d5’xfh 1§v Hal. 51%?ij gamut: _ dg‘xffi‘: alsrsfne d5 R e. R 5 Or: Hit. leH .sfde) ero" ,an/an 4%: 1'13th 9-“ ISOQ 31h 0’=s:mgo° = O This makes 013%: O fir [093% swam xjmfi §2j01§«5r Jae-H? shafim segmenfi é) a, d ANS- " s 10) Ear #1: Semficfrok , d§__L F” 1 m Idg’cF‘l: dsrsl’h “10": 0151” dsR 048 ygwaj4z£ wocjas = mar/M Aids tin r3 4n R3 4m“ 1' I ‘19” 4112 4K E Ctrc QB =3 + = WOT/005: M 'Tb‘ML fifflm 533$: Lag jig—{E ANS ’ 25p_ Four long copper wires are A20Acumcnt exists in each wire parallel to cach other their cross in the diraction shown in Fig. sections forming the comers of a 3042} WP“ maths magnitude square with sides a = 20 cm. anddnecnon ofB\atthc center of the squat? 55m. m Given: a: 206m 2 .0. 20m 6' = 20A erfim‘ dw'rfdfms EM: B“, @ poffl'f P £226}! wi'ni’ 1'5 m‘a disfance 7% fiam '1? - 50 SHEETS 12 Id! 100 SHIE'I'S 21-154 200 SHEETS 21-141 6 _ ammn Mdflflé’ht Pas/d dac in a /0)13,8#a:"fk7‘ Wu’rc M30633? “fie/d mm“ are aha/gr aéaw‘ Me ans of‘ 4 I'd)? Jim/717’ mire. mdjficfi’c 62M 45’ poa'm‘P due 7‘?) MM mks. is ##ja‘ 7% 7%6 and; ; p059)? fliraujh g or; shown 131 7%: 0427mm. 7% 09412521145 are 5mm 55 #re n3h+ Janina/e. ' - E 09rd. 0713 simijlb‘ Mn: is: 3%? {€5.30'G P‘ 7:30) '51: BICI+BC: 0;. +# r: 2&91; 3:. ‘rZ-flog‘ I resultant force acting p. Assume that a = 63.: $0601: AOxzo’zm lo 2 3.0m = 8.0 r/O'Zm L: Som=o.$OM 50 SHEETS 22-142 ‘IOD SHEETS 22444 200 SHEETS 22-14] 50) find H19. fine on each wire on“ Hue loop. bk, ‘J Eb: "B? (USI'rlj n’jh'f ’76???de “’98 :‘5 date '63 Hie 1‘0? wr’re Carrgmj c}. If {S €x‘7leffl4/ 7:0 Me hop) ll! [,2 2nd L‘Iengfi.’ drypurafi'zm (dz. BD-/‘/ , p- 735) ,a, For F; and if: firm be’fo’é’n Fara/{d wu’rfls car/3:113 Camenfi fF: - ;F0r H16 da'rcoh'ms Para/H cam-mt: «War/7; ' dim‘zpdrafle/ Cums/11's R? 53:33)"? Pd 3 p.733 or all» LL] 32. Zn (Mb) 4— H32) __f__ f. wo'zm $0 ”50'1”“ j . j 1 )fi! Q9 14% “ _ @+2—1}A "244 ,— W 3 5O SHEETS 22 Id! 100 SHEETS 12-144 200 SHEETS 21-14] in» given by Znoid «(4R2 + d”) (b) In what direction does B point? B— Vour‘ W5 Apphjrnfl Hal‘s in ihe 0433mm: 5;: le+B1x= B.ao.se+ Bzmse =(B.+Be)cos€9 Cose= 7:- Era (0113, Shelia“ wire 5- jg‘k (61301:, P730) Sp: (21:: *éfivézi— :gzfirjdg) JRM— migiia 3—2:”(a-fl—éiwiiém . Mm! 371’. Two long wires 3 distance d apart carry equal antipanallel currents i. as in Fig. 30-54. (a) Show mm the magnitude of the magnetic field at point P. which is equidistant from the wires. is Cji‘i/Bi’}: d] C .id Frid= a)5how8 2% b) di‘reefi'on m" 8—: Fi'ryr look a4 #13 magnea‘it fiefd due is each wire: The 315101 "“5 3"“ and“ Us: 44w: Mano! %' N&‘% ‘ “All {0 {‘lgfik’ Once I © \/ Armin 0"” 3 99M} , ' \ WIRE i I 9“" “mm" m ”M w®me z )2 | So {410. md9mfi‘c fiefdw‘n a n3n+ Paf'itkldrp orfl+ IS #0 Hats K /{ direcflm 0H: wrrtni $1, Carlin ”We di'ieoh'm 01? B". (B, and 52am flawed/3 Chase” fir iii/wave parpases) For “3 B we chose, 44w: is an 63%! and oppasi’k 32 The 5' - corn orients (40cc! air): a. mi 5;» IBP Ihfiex'df'wbm ’ ‘ 4N5. in 6b) eg- :1) new 46F. Figurt 30-62:: shows a crass section of a hollow cylindri- . cal conductor of radii a and b, canying a uniformly distributed current i. {a} Show that Mr) for the range b < r < a is given by poi r2 - b2 = 2mg: — b!) :b} Show that when r = a, this equation gives the magnetic field magnitude 3 for a long straight wire; when r = b. it gives zero magnetic field; and when E: = II]. it gives the magnetic field inside - a solid conductor. (c) Assume that a = 2-0 cm. b = 1.8 cm. and £= 100 A. and plot B(r) forthcrangefl 4: r< 6cm. 50 SHEETS 21-}!!! 100 SHEETS 12-144 200 SHEETS 22-14] a) 053 Anpmrs Law: §>€d§~ 34,4,“ §§£=§3Asc¢d* 3‘95: 32m" 75% MM we hm {MM énd- 59m (mg dismbukd, 3' C‘é‘fffi fin carrmf :5 and: circle- anm-w : 59 t 432) IT (a 1 “b 7') (I I :15 (MM; :~ Leno TTCFZ‘b‘) ‘4') (‘eflc 'é' 50') _ L J" WaZ-b‘) : §1§d§= Berr: got. (fit-b? : $42.6. 21m (:1 2-491) 14151 ((92492) 2 Zfib (a L-bz) O i 30) when b=O3 I407?) math «His 15mph, we allow! 80*) r m: anv/u‘m 719 5 - 3’2}. 3(0- .1277!" Fab: BQWYVJMAC b) 500 z bes Isf’hc majnch‘c 3d! fira fang, War’jm mm; BODY XML £4“.- EZ: flair 2 7111's :3 Hr. magndfc fey 15m JAM 667142575X 2m- (52 znaz {or r<b and rm. 1 0- 3%» I give” -' 6352.007: Lo: l-Sax L" A9024 5110110: 5: Bosfl r‘-b" __.- > 1’ Néz—b1)(¢ )Jbvza b) M: 5m: #22 pf, 30—5 2111' r=bt BU) =0 _ 5’01 60): Juli—C pf, 30—22 g 2w C) Plof ECO-Br adv-(baa. ! I Curfen'I-fin a mm; «644%: magrrhz field (the: #m} aw airmIAr (0:155. We (Kn pfdce our Amman foop 6‘le 1 one 043 +hese fiefi ”w; .r'h Me (€34!st o4 i Jack/35+ -‘ lo<r'<é2. 4+ 6?an Parh’addr E Pofnf, (B‘md E‘arc Mnjad- “b 4410:» Z “,sz ZNr‘Ka 1492) ANS. ! K @1va a } 3.20%! ,bZI-3M,C30-4cal’ Cfuafdnd oppqsa'k current) I." 12 0A firfi a) 5(r<c) b) 3(ccr4b) c.) B (Ecru) ol) 8 (r M) _ 6) Special Cam; 0'! Bk) RPM" 30) Ear or Y'CSOM. 471’. Figure 30-62!) shows a cross section of a long conductor of a type nailed a coaxial cable and gives its radii (a. b. c). Equal but opposite cummts I' are uniformly distributed in the two conduc- tors. Derive upmsions for 80-} in the ranges (a) r 4 c. (b) c < r C b, (c) b < r < a, and (d) r> a. (a) Test these expressions for all the special cases that occur to you. (f) Assume that a = 2.0 cm, in = 1.8 cm, :- = 0.40 cm, and i = 120 A and plot the function Bk) over the range t} d r < 3 cm. 50 SHEETS 22 I42 100 SHEETS 12444 200 SHEETS 22441 6 _mm 5x #1? solufi'm '10 CH30-46R 91* an Pmpenkn bop”) eacfiofflz ! ”31M o'r Ihkrfsfi i Flhd t. CJJ="'1' £6329; attenczflz at) NC. §7§ -ds- Ban vaprém on "C "r 2’ v Bdrm) if. Jacir (53> lw c<r<b= J/JL’ - 1' lb) 8’27” awake 7”” "5 ch‘r‘b5" zm- FMS. firstgwfigi .1. . M“ ‘ 7 E . “.4... - cm, -£_.r.(r~b’- iC)b4l"-Kd- BZHF-flatflc F’hd 1;“ : I 11m: ‘3?) ”-6.: ~b1)—')m ' (£3401)? i :L— I. (2‘ bl) I A’f‘ '3 z _b) gwhflgdzz :- -!_ r - 7' [71"]?! 2 Ba" '1“): ZTTF az—szz‘fi’ 2nr MKaivb‘L] 27W d) rm: anr—‘Jllo aim- 71., (61‘): O *‘BCr‘ch-t‘ 0‘ 3mm #2 meat: are, “5' ' Pf“! ant/m 0mm «mm. : IjtS“-)Spe ad 6&' i r=a m 360““): O 7'50 50‘3“)?“0 ’5 'hrue r=b=c (solve! 06147112): In 5010‘ J’s—9 WM v. 2m: 23¢ znr‘ [In 8624.139): 412-9 same ”(693"! TH“ | :‘n 8(bcrm): "£15: [6;]? '37 L ”45 fxwokd PH 132 Suggested Problems NéHE g (/3... ...
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