ph132s04_hw8 - PH 132 SPRING 2003 HOMEWORK # 8 Assigned:...

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Unformatted text preview: PH 132 SPRING 2003 HOMEWORK # 8 Assigned: 03/03/03 50 SHEETS 22-442 100 SHEETS 2244‘ 200 SHEETS 22-141 Q 51P.Acapacitorwifl1aninitialpoteufialdiffwcnocoflmVis dischaj'gedtlu'ougharesistorwhenaswitdabeiweenflmnisclosed au=0.Atr=lo.Ds.mepotentialdifiemneacmssmccapacitm -is1.00V.(a}Whatismetimcconstantofflrccirwit?(b)Whatis flunolcntialdifictmoeacmsslhecamcitoratt=l7flfl ssm GWEM. a Q T=09 Q 7-3205. K _. : f2 V0153 .-.. 336x/O V 50 SHIFTS 22-1402 100 SHII'I'S 12444 200 SHEETS 22-14! 7% 4?: An electron that has velocin 17': (20 x 106 mfg): + (3.0 x 106 szfi moves through mmmi = (0.0301)? — (0.151)i.' (a)F'mdflIeforocond1celaecumL(b)Repeatymcalc1flmfimfor apmmnhavingmesmnevelocily. - 63-65 7792-006 ' o _aao A a. Mom»: at. A A.— = ix:- A A... lx‘l" A .. Amos-'2 in‘ 0 br>0 glut-2A '. V = ones-'55? +C3. onoé’g—BT —I- E, r- (0 .050??? —(O.IS'IS A .3 I\~\ 30 SHEI‘I’S 22443 100 SHIE‘I’S 22-144 200 SHEETS 22-14] ® 5H2? - [6 E 16?. Ancleclronis aocclcmedfmmtestbyapotcmialdifferenoc of 350 V. It then 5mm a unifom‘l magnetic field of magnitudt 200 mT with its velocity perpendicular to the field. Calle (a)fl1espeedofmeeleclronand(b)thcmdiusofitspafl1mthe magnum: field. 1-7: BECAUSE TRIS-Is AN Nb. ate-cm 4'7" van-z. MOVE a» A 2912. 93:05:12 To THE bfhap E. 6:: 7 Am 2’ ARE AnTl-PAMM-EL H3225. "TM THE égwnéh WION THERE A MAG-MEI?”- Flm- _. _ ' Mi: Hap—E VM3 3 A1}; mmbLUMR. _ I . 951m— Nawrou's 23"‘Q MM 5 fur—5:610» 2F; “Max Fm‘T' - (H 50 SHEEYS 22-142 I00 SHEETS 22-144 200 SHEETS 22-14] 6 mm 28?. In Fig. 29-34, acharged par- ticle moves inxo a region of uni- form magnetic field 5. goes though haif a circle, and [hen ex- its that region. The penicie is ei- ther a pawn or an electron (you must decide which). It spends fig. 29-54 Problem 28. 130 ns within the region. (a) What is the magm'mde of?! (b) If the particle is sent back through the magnetic field (along the same initial path) but with 2.00 lirpes its previous kinetic energy. how much time does it spend within the ficld? ‘—' ‘PROWIE 7’45 gran}; 1325;221:3517: .Ib-JTHE’ FIGURE. @295 246»?- WB 71% i I l | l i | i “E. A lmgfilLofwirecan-iesaamcmi. Showmmifthe ~ ' fom'sed inn) a circular coil. than the maximum torque in magnetic field is devcloped when the coil has one turn that maximum torque has the magnitude 1' = inBMw. ,IF N cmsé‘b 0126424191 Loo?s dig FERMEZ: earn} A Own; :2? Lgmrfl L __._._____.—.._..___._._____._________9. THEN EACH L007” H45 A ozcvaEkimcg 50 SHEETS 22-142 “)0 SHEETS 22444 200 SHEETS .. :07: __L... t E I N “‘50 fi- : 2%.? I my. ' -_. __L_—__._ 5 WM II P I" =N:A =Ni<LZ HWN" T 7. E# ‘l'n’N _ auHEM — Au Ex 7:5ka AL eugficl "‘25 77+: oz; yew/c, 2x752): MCE A TDLQL): ; I}, (74 50 SH"?! 22-!42 I00 SHIE'IS 22-l44 200 SHEETS 22-h“ 6 mm HP. Flgm29—3sshawsawood cylhxlerofmassm = 0.250“ andleungL=0.Iwm,wid1 - meplancofdmwireooilmms dwaxisofdnecyiinder.Whalis -'- H makmmidnouglmleooil ' _ fill-rill preventflncylinderfiom rolling downaplane inclined fingleflmmemindnmofavafid uniform field of magifitude 0500-1". if the plane of the coil is iii-allein imiimd plane? ssm B= Soxr’o‘s?‘ fl= 30w=0.30n4 b= 40m =0w/0M C: 5000M 0.50M 60/0 b)?“ b/\ A I.\ '2 ‘ ‘3 J M “’36 50(u-h’on afpok mm and 407m 4;) m 2}“) AF! {mfg I Imp) ' are {Ook' 5r #1: m dee of : H94 “509615 " MW; '5 5 (.42 it wig: rhsmfib'hxam e: ’ A M “ ” = 508 Z . of 71a carzm‘ arm madfirmfybeam if 5: m9‘ ‘ MS made-d as W 7%: mdjgdak We bar: Mum/W ('2‘ 1.3 (mwrdkaar,érd Chum at Code (I: m .4 {hr same Wed». gar/4": fzsa'lfiem': +54 +1 ar- (e. drawn can, a rij Ala/rule, rm our 177?”; m I aWEMM cf #1: gar/W, oar #flm‘v‘b fights fie #6465»: iofflfln/fl‘“ -' k. 9b) I’W‘TVBsth €=?t9° I 22 Mu] 50 SHEETS . 22-]42 100 SHEETS 22 I44 200 SHEETS TWS -‘ (O-BOAmZ)(SOx/o"3T) r Am We: 73 WM? dmfiwd Km 1%: ngm fraud mé: 4 A - ifi7gg=fl£xstw5f¢x3 “‘41 . Fug? ' 50 SHEEYS 22-1‘2 100 SHEETS 22 I44 200 SHEETS 22-141 @ ' cimular wall clock has a face with a radius of 'Sixumofmmwomflmundilsperhnum'filewirc of 2.0 A in meclockwise diraction. The clock is '-'j-..- When than is aconsumt, uniform externalmagneticficld 2' 55;... 70 1111‘ (but the clock still keeps pexfea time). At ' - Imp.m..flwhourhandofd3eclockpofillshlthedhectim 4-"; a : magmficfield.(a)Aficrho%-manyminmcswfllflm - pointinlhedimction oflhe totqueoutlwwindingdnc ' ficld?fb)Fmdfl1etorqucmagnimde. cm’0J5n1 : Eiéjtfinirrfs z _ N:(0 3 5-320}! dockwilse. 8-“ 70% 7am? MW w/ 1 g a) ab'reasanoat F“ f 9 l ! b) magmfide. 0? ’F” a) waa ' ' fipoMfi {Mb {I} «@6ng 1‘» 6824-66) 31‘ a 3 J lib) ?=FK§;MBsh?O° 718 = Ala/45 =A/e'(m'z)B . =do(zWrwme-s»-mus- dilute axes, with A3 = 20.0 cm, BC = 30.0 cm. and FA 10.8 cm. Calculate the magnitude and direction of the magnetic: dipole moment of dais loop. (Hint: Imagine equal and opposite’ currean i in the line segment AD; then treat the two rectangular loops ABCDA and ADEFA.) 50 SHHTS 22-142 100 SHEETS 22-144 200 SHEETS 22.14] a r 2940 shows 21 our-- — ABCDEFA carrying a -.s = 5.00 A. The sides of " '3 "- 35?;- parallel to the coor- L ijan: i: 5.00 :4 AB: 20. 0am: 200!” 3C: 30-0034 = 0.500314 FA: mo an? 0100M . -—-".> - I/u. {5r ABCDEFA “‘3’ 2 “*5? ~-‘-:. I/allBCbEFA flew 1;“ HDEF ' fl: My? =(I/l (IO-w!) Waging)” (FAXBC) we! 'Hl-e n'HhMJm/c 1b 367‘1‘51 J'thfie r each/a”? “A, 2 - ' é '- l . M fimm (500Afl0100m)(0.300m)d (5.00m zooMyo 309 )k ': 14“ z ' 0.!50HMJ 0.3001931» ANS 6= 12m" 3.0}?5): ('n W 83 p/dne. Ms. m WWW-«m... 50 SHEETS 22-142 100 SHEETS 22-344 200 SHEETS 22-14! a i ' J..._.._..._ Qw= I= 5.0/4 (—5) SIP. A long. rigid conductor. lying along the x axis. carries a current of 5.0 A in the negative direction. A magmlic field B is -’> present, given by B = 3.0i + 8.0x1j, with x in meters and B in B :81)? + 0 x1. )M'r‘ milliteslas. Calculate the force on the 2.0 :1: segment of the com J ductormatliesbetwnenx=lflmandx=10m far/,0," Consa'defa small 5:19am)“ dfl’ -' affidfxé" d§=fdxfx Eb Now {Mamie 40 find 4%.: ' X2 7“: A __ B j*‘“dx.«:x5 = 4 dxr~£’)x(3.oa+g.0x=“) XI Kl - ' (/Z’ 1's m #2.! same dare-chm as #K curred: of? ’ -dx£“ _ M/ flora: 52m” 7:, dad are : : _- ("LO mgw‘OWVB-ono - (wk/8]": " 4‘5- PH 132 Suggested Problems \L. 50 SHEETS 22442 "10 SHEETS 22444 200 SH“?! 12-I41 ® CH 2W4? HRwS‘ 49P.Annralwircofmassmslidcswidmulfiicfionontwo - . hmimnml-nilsspacedadisnnocdapan,asinfig.29-44.Tbe Gil/CH! V030,m,d,5,6 txackliesinaverticalunifummagneficfiddBJhemisaoon- "‘— stantmmtifluoughgumtorfi.alongoncrail.acrossthe wire.andbackdnwndwomcrrail.Fmdflwspeedmddiractionof y drwh‘snmfimasafilncfiunnffimmmingillobemfion- ._.——- ary at: = 0. a, ' g [5 ad’ oF-I’ne p03: 0 Majncfi'c Farce am Car/w Ctr/513 wire. If we find 1%: 15m on: Me Mire, me am 1904’ ('15 «(e/émflm 4nd v’e/m'y. ‘—‘? . I; = a EVE” we mafiade 0.: gang/p.- a ‘ E: :‘s in H1: Jrkeafiarz,w out team 19m hdn'ajm. Z” 6 :31 Me Meafm ma 1%: Car/W mm are) W) :‘n wire : fl? file/fidan 0" Pb 7%: Affij/fi JFW Mirch Jo, Z“. "a"? =C'“d€)x3‘5‘t'dfiffixw'dsefilen' WM/méfifieaw : .. - A 1 padda‘. Ram yaw 19050:: I)! fie aficdfin 1 f5, W’B‘J 6! #¢ firsf lifting Car/Hem m, :‘n 7%: wfiek flmwaém’g}: m deMof fiexcma/ (Icahn 5%” ' ’ MM 1" I3 fiW/fi’fl/(eémfi'm, 50 final!) 3AM“ I" die a fit m - £5 4 0 —-§ V"= waft = {gt = 1451-3 - m MS FIGURE 29-44 Problem 49. —=-. 5: mm. 1;. #151me r€= U . ...
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This note was uploaded on 04/23/2008 for the course PH 132 taught by Professor Ramsdell/wick during the Fall '08 term at Clarkson University .

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ph132s04_hw8 - PH 132 SPRING 2003 HOMEWORK # 8 Assigned:...

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