exam_2 - CHEMISTRY 2A-c Hour Exam II Feb 28, 2003 Winter...

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1 CHEMISTRY 2A-c NAME ______________________ Hour Exam II T. A. ________________________ Feb 28, 2003 Lab Section Number ___________ Winter 2003 Lab Room ___________________ Lecture: MWF 2:10-3:00 pm CLOSED BOOK EXAM – No books or notes allowed. Place all answers in the space provided. Be sure to write your name, your T.A.’s name, and your Lab Section Number in upper right hand corner. This examination contains 3 questions on 5 pages. Question Credit I. (60 points) II. (25 points) III. (15 points) Total (100 points) Avogadro’s number: 6.022x10 23 #/mol PV=nRT KE=(1/2)mu 2 =(3/2)kT E=h ν c= λν E=-A(Z/n 2 ) ν =R(1/n 1 2 –1/n 2 2 ) P=h/ λ R = 0.08206 L-atm/mol-K = 8.314 m 3 -Pa/mol-K = 1.987 cal/mol-K = 8.314 J/mol-K
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I. (60 pts: 2.5 pt each unless specified) Multiple Choice 1. (2 pts) Which pair of elements below should be the most similar in chemical properties? a) N and O b) P and S c) K and Ca d) Sr and Ba e) K and Mg 2. Which of the following atoms would be expected to release the most energy upon receiving an electron (i.e., forming an anion with –1 charge)? a) Ba b) Ca c) Br d) O e) S 3. A certain atomic orbital contains an electron with quantum numbers n=3, l =2, m l =0, m s =+1/2. If another electron were to be replaced in the same orbital, its quantum numbers would have to be a) n=3, l =3, m l =-2, m s = -1/2 d) n=3, l =1, m l =1, m s =+1/2 b) n = 2, l = 2, m l = 0, m s = +1/2 e) n = 3, l = 2, m l = 0, m s = -1/2 c) n = 3, l = 1, m l = 0, m s = -1/2 4. The electron configuration of Cadmium (Z=48) is a) 1s 2 2s 2 2p 6 2d 10 3s 2 3p 6 3d 10 4s 2 5d 10 d) 1s 2 1p 6 2s 2 2p 6 2d 10 3s 2 3p 6 3d 10 4s 2 4p 2 b) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 5s 2 4d 10 e) 1s 2 2s 2 2p 6 2d 10 3s 2 3p 6 3d 10 4s 2 4p 6 5s 2 5p 6 5d 4 c) 1s 2 2s 2 2p 6 2d
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This note was uploaded on 04/23/2008 for the course CHEM 2A taught by Professor Guo during the Fall '08 term at UC Davis.

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exam_2 - CHEMISTRY 2A-c Hour Exam II Feb 28, 2003 Winter...

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