Exam 3 - I - I. : " 'i . .Ii.- - e " I...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: I - I. : " 'i . .Ii.- - e " I " . . i . . .. - Nttmc:~._ '“i' -' Fri-g f Huff? L10 Sectten:__t_li1o2l_ilA Examfi‘verii Multiple lChoice: 32 Questions. 2 points each, til-4 points total I} Gene 3 controls the sharpness oispines in a type ol'eaettts. Caetases with the dominant al!c|e, 3, have sharp spines, whereas homozygous recessive ss eacttlses have dull spines. At the same time. a second gene, N, determines whether cactus-es have spines. l-lotnozvgoits recessive nn eactases have no spines at all. It dottth heterozygous '3an cactttses were allowed to self—pollinator the FE would Segregate in which of the following ratios? _ U sharp—spined : 3 dull-spitied14 spineless; H] 9 sharp—spined : T" spineless IE sharp—spilled : 3 dttil-spined .' l spineless: D} I sharp spined: l dull—spined: l spineless 2} IE sharp—spined :4 dtill-spined 2} A woman and her spnnse hoth show the normal phenotype For pigmentation. httt both had one parent who was an albino. Albinisrn is an aatosornal recessive trait. it their first two children have annual pigmentation, what is the probability at their third child wiii he an alhino'.’ :1 If: e I ante; (B t4; c} l: D} tint; E} o ' ' -'-—._.'_.__|__4' Pi} How would one explain a testcross involving 1“] dihvbnd flies in which more parental-[vine offspring than recombinant—type. offspring are produced?1 n] The two genes are linlted‘. It Recombination did not occur in the cell during meiosis; {I} The two genes are unlinked; Both of Ihe characters are controlled by more than one gene; Ii] 'I‘Iie testeross was improperly pertonned. 4) Map units on a linkage map cannot he relied upon to calculate physical distances on a chromosome hecattse: M the relationship between recombination I'rettuenc}.r and map units is dil'lerent In every individual; I3} physical distances between genes change during the coon-Le oil—the cell cycle: {I} the frequency of crossing over varies along> the Iengl I1 ol' the ehroniosonie: _ the acne order on the chromosomes is slightly different in every individual: all of the ahove fl I [1 III lej.- :3} The pedigree in the above Figure shows me transmission ol'a trait in a particular family. Based on this pattern ol' transmission. the trait is tnost likely: .. t1) sent—linked necessivc: H} atitosolnal recessive: {I} rnitoci‘tondrial; sex—linked dominant: Ell :tetosotnal dominant. I B page i til it} l EtieEttlA Exaniil‘u’erfl Multiple lTheme: 32 Questiene, 2 penile eaeh, {HI puinte Ltital It (Jeni:- S eentrele the sharpnesw. el'epinee in a type eteaetus. Caeteeee with the deminant allele, 3, have sharp spines. whereas hemeaygiiae reeeeaive es. eeetusee have dull shines. At the same time, a eeeend gene, N. determines. whether eaetuses have epinee. Hemeeygeae reeeeeiire rin eaetaeee have no spines at all. If deahly heterrixygnus SeNn eaetueee were ttllewetl te eell—pflllinate, the F2 wttttltl eegregute in whieh til the fallen-'ng ratiea'l‘ U sharp—epined : 3 dull—epined _' 4 spineleee: B] 9 eliai-{i—epined : 7" spineless l2 sharp—epined : 3 dull—epined : 1 spineless: D} I sharp epined: l dall-spined: l spineless. ‘ ..} I2 Hliaqi—enined :4 dull-xiiined 2} A weinan end her epeaee l'tflll't shew the normal plienetype fer pigetentatien, hut hath had erte parent whe was: an fllhintt. Alhinifim ir‘. utt :iuttteemal reeeesive trait- ll' their firm Lwe eliildt'en have net-real pigtnentatittn, 1what it; the pl'tll'fittlllliLJfJLlHEll their third child will he an alhinii‘? I» __fl-. [2: wire; r e :4; e) l; m 3:4; 3' E} e it; flew WfltilLl tine explain a teetet'tien' involving Fl diliyhtid flies. in whieh mere parental—type ell-Spring than reeiitnhinant—type til'l'Hpri r13I are predueed'? A.) The twin genes: tlt‘t.‘ linl-ted; [I Reeei‘tihintttifln did not i‘t-eetlrin the eell during. rneieeie: {I} The thi genes are unlinked: @ Beth of the eharaeters are eetttrelled by mere than tine gene: E} 1110 teeterue}: war; in'tiiriiperli.r perturmed. 4;: Map units. en a linkage map eanniit he relied drain ltll ealeulate phyeieal dietaneee en a ehrerntisurne heeaiiee: M the relatinnehip herween reeetnhitiatinn tiieiitierieg,r and map unite is different in every.- individual; H} phyeteal dietaaeee between genes change (luring the C(‘Jllt'fifi er the eell cycle; {7} the t‘requeney UfL‘rflt—tfiltlg ever Varies. along the length til the eht't‘tmtieertte: 2)) the gene tirdei' til] the elimitieeemet‘. is slightly dil'lereiit in every individual; F. all {if the aheve 5} The pedigree in the aheve figure shows the ti'aiiemieeitin tila trait in a liartiealar family. Based ea this. pattern el' imnemiseinn. the trait ir- rniia't likely: n M sex—linked t'eeeeeiue; H} ttltlt‘tl-tttl'fitll reeeeeiiie; {It miteehendrial; sex—linked dominant; I‘ll 1t|JltJ$tlmtil dtitninanL _ B page 1 el'lt} ...
View Full Document

Page1 / 2

Exam 3 - I - I. : " 'i . .Ii.- - e " I...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online