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# HW1 - Problem 2-7 Determine the magnitude of the resultant...

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Unformatted text preview: Problem 2-7 Determine the magnitude of the resultant force FR = Fl + F2 and its direction measured counterclockwise from the positive u axis. Given: F] = 25 1b F2 = 50 lb 61 = 30 deg 62 = 30 deg 63 = 45 deg Solution: 0: = 180 deg— (93 + 61) FR 2 (/ng +F12-2 F1 F2 cos(a) 57R = 61:41? sin(0’) = sin(a) 0 = asin[sm(a) 2] F2 FR FR 0 = 51.8deg 9=€—@ gag: 6.8:deg Problem 2-13 A resultant force F is necessary to hold the ballon in place. Resolve this force into components along the tether lines AB and AC, and compute the magnitude of each component. j: Given: F = 350 1b 61 = 30 deg 62 = 40 deg Solution: FAB F sin(t91)i _ sin[180 deg — (91 + 02) 21 sin(t91) FAB _ F |:sin[180 deg — (61 + 62H] m V f 130 w (614.33}; . “‘6 FAB = 1861b FAC F F ' sin(92) : sin[180 deg — (61 + 92)] FAC = F[ sin(02) ] sin[180 deg — (01 + 92)] FAC = 2391b Problem 2-32 Determine the magnitude of the resultant force and its direction, measured clockwise from the positive x axis. Given: F1 =7ON F2=50N F3 =65N (9 = 30 deg ¢ = 45 deg Solution: i) FRx=2Fx; FRX = F1 +F2cos(0) ——F3cos(¢) +T FRy= ZFyi FRY 2 "F2 sin(6) - F3 sin(¢)‘ FR = «lFRXz‘I'FRYZ Problem 2-47 Determine the magnitude of the resultant force and its direction measured clockwise from the positive x axis. Units Used: kN =103 N Given: F1=20kN :31 || 40kN F3 =V50kN + f ‘9 FRx=2Fx§ FRx = F3 — +F2 -———— (m) i m2 FRx = 58.28 kN +T F Ry: EFyQ ...
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