EE 338_HW7_Solutions

EE 338_HW7_Solutions - 10/29/2007 EE 338 Fall 2007 HW#7...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
10/29/2007 EE 338 Fall 2007 HW#7 Solutions 5.5 (a) n-side: EE k T N n FF i d i −= F H G I K J ln = () F H G I K J 00259 510 15 10 15 10 .l n . x x or e V i 0 3294 . p-side: EEk T N n Fi F a i F H G I K J ln = F H G I K J 10 17 10 n . x or e V Fi F 0 4070 . (b) V bi =+ 0 3294 0 4070 .. or VV bi = 0 7364 . (c) NN n bi t ad i = F H G I K J ln 2 = L N M M O Q P P 0 0259 10 5 10 17 15 10 2 n . bg b g x x or bi = 0 7363 . (d) x V e N N n bi a da d = + F H G I K J F H G I K J L N M O Q P 21 12 / = ( L N M 2117 88510 0736 16 10 14 19 . . x x × + F H G I K J F H I K O Q P 10 1 10 5 10 17 15 17 15 xx / or xm n = 0 426 . μ Now x x x p = ( ) L N M 14 19 . . × + F H G I K J F H I K O Q P 10 1 10 5 10 15 17 17 15 x x / p = 0 0213 . We have ε max = eN x dn = −− 5 10 0 426 10 117 8 85 10 19 15 4 14 x x b g b b g g or max ./ = 329 10 4 xV c m 5.7 ) (b) nN kT OC CF = L N M O Q P exp af = F H I K 2.8 10 021 19 x exp . . or xc m Od == 843 10 15 3 . (n-region) pN kT OV FV = L N M O Q P exp = F H I K 104 10 018 0 0259 19 .e x p . . x or 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
10/29/2007 pN xc m Oa == 9.97 10 15 3 (p-region) (c) VV NN n bi t ad i = F H G I K J ln 2 = () L N M M O Q P P 00259 9.97 10 8 43 10 15 10 15 15 10 2 .l n . . xx x bg b g or bi = 0 690 . 5.8 (a) GaAs: , bi = 120 . nx c m i = 18 10 63 . xWx x pn + 02 .. p or x x p n = 025 . Also Nx x x N N dn ap p n d a =⇒ = = . Now n bi t i = F H G I K J ln 2 or 0 0259 2 2 l n . = F H G I K J N n a i Then 0 0259 2 2 . exp . . N n a i = F H I K or Nn ai = L N M O Q P 2 2 0 0259 exp . . or c a = 4.14 10 16 3 m (b) da . c d = 104 10 16 3 . m (c) x V e N N n bi a d = + F H G I K J F H G I K J L N M O Q P 21 12 / = 2131 88510 16 10 14 19 . . L N M x x × + F H I K F H I K O Q P 4 1 1 4.14 10 16 16 . / or xm n = 0 366 .
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/27/2008 for the course EE 338 taught by Professor Dapkus during the Fall '07 term at USC.

Page1 / 6

EE 338_HW7_Solutions - 10/29/2007 EE 338 Fall 2007 HW#7...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online