chem notes 9-21 - Combustion Reaction-C9H20 O2 CO2...

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September 21, 2007 Gen. Chem. 1 Dr. Stevens Review: Micro – H2O - 2 atoms of H for every 1 atom of O make 1 mole H2O Macro – H2O - 2 mol H for every 1 mol O makes 1 mol H2O If we have 36.0 g H2O, how many mol H atoms are present? How many individual atoms of H are present? - 36g H2O x (1 mol H2O/18g H2O) = 2mol H2O - 2 mol H2O x ( 2 mol H/1 mol H 2 O) = 4 mol H - 4 mol H x (6.022x10^23/1 mol H) = 2.4x10^24 atoms H Balancing Reactions: -rearrangement of elements -reagents products 1. write skeletal equation showing species as R or P (as appropriate). 2. begin finding coefficients for least used elements first. -multiple of molecule cannot change subscript 3. verify that we have equal # atoms on both sides of reaction 4. OPTIONAL: add state of matter if known (l, g, s, aq)
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Unformatted text preview: Combustion Reaction:-C9H20 + O2 CO2 + H2O-C9H20 + O2 9CO2 +H2O-C9H20 + O2 9CO2 + 10H2O-C9H20 + 14O2 9CO2 + 10H2O Demo-pink = 1 H2: 10 O2 (pop)-white = 10 H2: 1 O2 (fireball)-red = 2 H2: 1 O2 (pop, fireball, explosion, GROUNDSHAKING!!! = REACTION) Predicting Masses of Products Formed:-Limiting reagent problems-1 reagent is consumed before the other = limiting reagent-can’t make any more product-4NO2 + O2 = 2N2O5: if 138g NO2 is mixed with 64g O2, determine LR and max mass of N2O5.-138g x 1 mol/46g = 3 mol NO2-64g x 1 mol/32g = 2 mol O2-3mol NO2 x 1mol N2O5/2mol NO2 = 1.5 mol N2O5 possible-2mol O2 x 2mol N2O5/1mol O2 = 4 mol N2O5-LR: NO2-1.5mol N2O5 x 108g/1mol N2O5 = 162g N2O5...
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chem notes 9-21 - Combustion Reaction-C9H20 O2 CO2...

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