HW5_2006

HW5_2006 - 4-36. Normal Probability Plot .999 .99 .95...

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4-36. P-Value: 0.934 A-Squared: 0.143 Anderson-Darling Normality Test N: 6 StDev : 0.318852 Av erage: 16.9833 17.4 17.3 17.2 17.1 17.0 16.9 16.8 16.7 16.6 16.5 .999 .99 .95 .80 .50 .20 .05 .01 .001 Probability Fatty Normal Probability Plot The normality assumption appears to be satisfied. This is evident by the fact that the data fall along a straight line. a) 1) The parameter of interest is the true mean level of polyunsaturated fatty acid, μ . 2) H 0 : μ = 17 3) H 1 : μ 17 4) α = 0.01 5) t 0 = x sn −μ / 6) Reject H 0 if t 0 < t α /2,n-1 where t 0.005,5 = 4.032 or t > t α /2,n-1 where t 0.005, 5 = 4.032 7) x = 16.98 s = 0.319 n = 6 t 0 = 16 98 17 0 319 6 0154 . ./ . =− 8) Since 4.032 < 0.154 < 4.032, do not reject the null hypothesis and conclude the true mean level is not significantly different from 17% at α = 0.01. b) P-value = 2P(t > 0.154): for degrees of freedom of 5 we obtain 2(0.40) < P-value 0 .80 < P-value c) Using the OC curves on Chart Vb, with d = 05 0 319 . . = 1.567, n = 10, when β 0.1. Therefore, the current
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sample size of 6 is inadequate . d) For α = 0.01, t α /2,n-1 = t 0.005,5 = 4.032 xt s n s n ≤≤+ 0 005 5 0 005 5 ., μ 16 98 4 032 0 319 6 16 98 4 032 0 319 6 .. . . ≤≤ + μ 16.455 μ 17.505 With 99% confidence, we believe the true mean level of polyunsaturated fatty acid is between 16.455% and 17.505%.
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HW5_2006 - 4-36. Normal Probability Plot .999 .99 .95...

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