lab8 - Exercise 2 x=-3:0.3:3 y=-3:0.3:3[A,B]=meshgrid(x,y...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Exercise 1 x=-1:0.25:4; y=-2:0.25:3; [A,B]=meshgrid(x,y); D=12-3*A+2*B mesh(A,B,D) surf(A,B,D) I saved the second surface as the first, but am planning on emailing you the image for this first exercise when we are in lab Tuesday.
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Exercise 2 x=-3:0.3:3; y=-3:0.3:3; [A,B]=meshgrid(x,y); D=18-A.^2-B.^2 surf(A,B,D) Exercise 3 x=-2:0.3:2; y=-3:0.3:3; [A,B]=meshgrid(x,y); D=B.^2-2*A.^2; surf(A,B,D)...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern