Solutions2_SampleTests2

# Solutions2_SampleTests2 - Test II College Physics II Dr....

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Unformatted text preview: Test II College Physics II Dr. Asim Gangopadhyaya You must show your work to 2et full credit. 1. ~ ~ F-= ~tV xE . )--" <3 " 11 ,,13 ::;: 4, g)r; 10 K ~-II F:=- 7a (, X 10 . R N-11 1'\ Ci = - 7. b ~ 10 '" K ~-3J v q. II "X)O ~j Summer 2002 f\ ,..-'I. / ' '13= l".c;-rt., ":I/e Name ':" 2- + 2- . OJ ) '>( loT ..,. 1'1 A.--- 'go 3" X)O ~.k &'2- An electron, moving with a velocity of (2.4, 0, 0) x 106m/s enters an area where the magnetic field is (1.5, 2.0, 0) x 102T. Given that the mass of an electron is me= 9.11x 10-31kg and its charge is qe=-1.6 x 10-19C, determine the magnitude and the direction of the acceleration of the electron. ~ b-:'\ V .:: 2~ 4 y.. 10 <j; 2. Two parallel plates (of area .25 m2 each) are separated a distance of .1 mm. A sheet of paper (dielectric constant 4.0) is inserted between the two ~ plates to fill the gap between the plates. These plates are given charges 2JlC and-2JlC respectively. The electric field due to a planar sheet of charge of uniform densityais given by (E=a/ 2 eo),where eo = 8.85 X 10-12 81 a) Determine the electric field between two plates before and after the paper was inserted. b) Determine the surface charge density induced on the surface of the dielectric material....
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## This note was uploaded on 04/24/2008 for the course PHYS 126 taught by Professor Gangopadhyaya during the Spring '08 term at Loyola Chicago.

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Solutions2_SampleTests2 - Test II College Physics II Dr....

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