Fund. L - Mole Ratios & Volumetric Analysis

Fund. L - Mole Ratios & Volumetric Analysis -...

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Sulfuric acid forms in the following chemical reaction SO 2 + O 2 + H 2 O → H 2 SO 4 1 st – Balance the equation!!! 2 SO 2 + O 2 + 2 H 2 O → 2 H 2 SO 4 L.1 – Mole-to Mole Predictions How many moles of H 2 SO 4 will you make if you have 2.4 moles of O 2 ? 2.4 mol O 2 x 2 mol H 2 SO 4 = 4.8 mol H 2 SO 4 1 mol O 2 L.2 – Mass-to Mass Predictions How many g of H 2 SO 4 will you make if you have 400 g SO 2 ? Convert g to moles: 400 g SO 2 x 1 mol SO 2 = 6.24 mol SO 2 64.06 g Mole to mole ratio to find moles of product: 6.24 mol SO 2 x 2 mol H 2 SO 4 = 6.24 mol H 2 SO 4 2 mol SO 2 Mole to g conversion to find g of product 6.24 mol H 2 SO 4 x 98.07 g = 612 g H 2 SO 4 1 mol H 2 SO 4
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L.3 – Volumetric Analysis Amount (moles) in the titrant (solution in the buret) are the exact amt need to react with the amount (moles) of analyte (in flask) Same as above – but need to know M = moles/L A sample of vinegar is to be analyzed for its acetic acid content. A volume of 50.0 mL is measured out and titrated with a solution of 1.306 M NaOH. 31.66 mL of that titrant is required to neutralize the solution. What is the concentration of the acetic acid in the vinegar (moles per liter). CH 3 COOH (aq) + NaOH (aq) → NaCH 3 COO (aq) + H 2 O (l) 1.306 M NaOH = moles = 0.0413 moles NaOH 0.03166 L 0.0413 moles NaOH x 1 mole CH 3 COOH = 0.0413 moles CH 3 COOH 1 mol NaOH M CH 3 COOH = 0.0413 moles = 0.827 M solution of CH 3 COOH 0.0500 L
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Fundamentals L - Mole Ratios & Volumetric Analysis Questions 1. Sea water contains roughly 28.0 g of NaCl per liter. What is the molarity of sodium chloride in sea water? 2. What is the molarity of 245.0 g of H
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Fund. L - Mole Ratios & Volumetric Analysis -...

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