Fund. G - Solutions &amp; Mixtures

# Fund. G - Solutions &amp; Mixtures - Fundamentals G...

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Unformatted text preview: Fundamentals: G Mixtures and Solutions Molarity – amt of solute in a volume of solution c = n/V c = molarity (units are moles/L) n = moles V = liters Ex. 734 g of lithium sulfate dissolved to make 2500 mL of solution. What is the molarity? 734 g Li 2 SO 4 (1 mole/109.95 g) = 6.676 moles Li 2 SO 4 2500 mL = 2.5 L 6.676 moles/2.5 L = 2.7 M Dilutions – when a solution is diluted, its concentration of solute molecules is reduced by the addition of more solvent C 1 V 1 = C 2 V 2 Ex. Calculate the volume of 0.0155 M HCl (aq) that we should use to prepare 100. mL of 5.23 x 10-4 M HCl. C 1 = 0.0155 M V 1 = ? C 2 = 5. 23 x 10-4 V 2 = 100 mL (0.0155 M)(V 1 ) = (5. 23 x 10-4 )(.100L) V 1 = 0.0337 L or 3.37 mL Fundamentals: G 1. Calculate the molarity of 25.0 grams of KBr dissolved in 750.0 mL. 2. 80.0 grams of glucose (C 6 H 12 O 6 , mol. wt = 180. g/mol) is dissolved in enough water to make 1.00 L of solution. What is its molarity? 3. 53.4 mL of a 1.50 M solution of NaCl is on hand, but you need some 0.800 M solution. How many mL of 0.800 M can you make?...
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## This note was uploaded on 04/24/2008 for the course CHEM 6A taught by Professor Pomeroy during the Winter '08 term at UCSD.

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Fund. G - Solutions &amp; Mixtures - Fundamentals G...

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