14 - ECSE-2610 Computer Components & Operations (CoCO)...

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ECSE-2610 Computer Components & Operations  (CoCO) Fall 2006 Review for  Midterm Exam #1
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MIDTERM 1 Thursday October 12, 2006 10-12 Section 1 in DCC 232 & 235 All other sections here in AE 214 One-sided 8.5” by 11” sheet of notes No book, notes, computer, calculator: pen or pencil only In-class review on October 10 Q&A in Studio on October 11 Grades posted on WebCT by October 19
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Material for MT 1 Chapter 1 Chapter 2: Section 2.1-2.6 (except subsections 2.5.5-2.5.7), 2.10-2.12, 2.15 (as covered in class) Chapter 3 Chapter 4 Chapter 6: Sections 6.1-6.9 Material on slides posted on WebCT (including these slides) Labs 1-5, HW 1-6
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Missed Exams or Assignments Marks for any missed Homework, Studio, or Midterm will be made up by extra weight on the Final Examination. e.g., If you miss a midterm, your mark on the final examination will account for 40% instead of 25% of your grade.
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Email Prof. Nagy: nagy@ecse.rpi.edu Spam filter sometimes eats your message. Less likely with your .rpi handle. I check my email every day, but spam filter only once a week. Prefer face-to-face to telephone. Tomorrow I cannot check my email before 7pm. Prof. Vastola: vastola@ecse.rpi.edu Will try to check my email often.
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    Seminar Tomorrow Wednesday  4pm  Sage Auditorium David Stork  (Ricoh Innovation) " Did the great masters 'che
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ECSE-2610 Computer Components & Operations  (CoCO) Fall 2006 Ch. 2:  Number Systems
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Representation of Numbers Base 10 representation: N = Σ N i x 10 i with N i {0,1,. . .,9} Binary: N = Σ N i x 2 i with each N i {0,1} Hex: N = Σ N i x 16 i with N i {0,1,2,. . .,9,A,B,C,D,E,F} You should be able to convert between any of these. Positional Number Notation: Positional Number Notation: Weight of each digit determined by its position.
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Binary Addition:   Similar to the Decimal  Case (carries) 1 0 2 = 5 10 + 1 2 = 3 10 = 8 10 Example: Add 5 and 3 in binary 1 1 1 0 1 1 0 1 1 0 2
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1 Binary Subtraction:   Similar to the Decimal  Case 1 0 1 2 = 5 10 - 1 1 2 = 3 10 1 0 2 = 2 10 Example: 5 - 3 - 1 0 (borrows) 1 0 0 0 1 1 2 = 3 10 - 1 0 1 2 = 5 10 1 0 2 = -2 10 1 Hanging borrow tells us that result is negative Example: 3 - 5
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Number Systems:   Representation of Integers 2 major schemes: signed-magnitude and two’s-complement Two’s Complement is much better for computers. Example : Two’s complement representation of -7 (as a 4-bit binary number) 2 4 = 10000 sub 7 = - 0111 1001 = representation of -7 Easier Way 7 = 0111 Take the bit-wise complement = 1000 Add one +1 1001 = representation of -7
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ECSE-2610 Computer Components & Operations  (COCO) Fall 2006 Ch. 2:  Basic Boolean  Algebra and Digital  Circuits
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3 Basic Boolean Operations Z = X also written Z = X' Boolean  Expression Inverter Z X Gate NOT X 0 1 1 0 X Truth Table Z = X + Y OR X Y Z X OR Y Y 0 0 1 1 0 1 0 1 0 1 1 1 X Z = X • Y = X Y AND X Y Z X AND Y 0 0 1 1 X Y 0 1 0 1 0 0 0 1
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4 Other Important Logic Gates Gate X Y Z NOR (NOT OR) Z = X + Y NAND Gate X Y Z
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This homework help was uploaded on 04/22/2008 for the course ECSE 2610 taught by Professor Ji during the Spring '08 term at Rensselaer Polytechnic Institute.

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14 - ECSE-2610 Computer Components & Operations (CoCO)...

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