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Chap005

# Chap005 - CHAPTER 5 A SURVEY OF PROBABILITY CONCEPTS 1...

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C HAPTER 5 A S URVEY OF P ROBABILITY C ONCEPTS 1. Outcome 1 2 1 A A 2 A F 3 F A 4 F F 2. Outcome 1 2 1 A A 2 A R 3 A S 4 R A 5 R R 6 R S 7 S A 8 S R 9 S S Chapter 5 45

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3. a. 0.176 found by 6/34 b. Empirical 4. a. 0.40, found by 2/5 b. Classical 5. a. Empirical b. Classical c. Classical d. Empirical, based on seismological data. 6. a. Outcome 1 st 2 nd 1 M M 2 M F 3 F F 4 F M b. Classical 7. a. The survey of 40 people about environmental issues b. 26 or more, respond yes for example c. 0.25 found by 10/40 Chapter 5 46
d. Empirical e. The events are not equally likely but they are mutually exclusive 8. a. Recording the number of violations b. at least one violation, for example c. 0.009, found by 18/2000 d. Empirical 9. a. Answers will vary, here are some possibilities: 123, 124, 125, 999 b. 3 1 10 � � � � � � c. Classical 10. a. Answers will vary, value goes up 1/16, goes up 1/8, goes down 1 b. Answer depends upon when the data are collected c. Empirical 11. P(A or B) = P(A) + P(B) 0.30 0.20 0.50 P(neither) =1 0.50 0.50 = + = - = 12. P(X or Y) = P(X) + P(Y) 0.05 0.02 0.07 P(neither) =1 0.07 0.93 = + = - = 13. a. 0.51 found by 102/200 Chapter 5 47

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b. 0.49 found by 61/200 + 37/200 = 0.305 + 0.185 Special rule of addition 14. a. 80%, found by 50% + 30% b. 80%, found by 100% – 20% 15. 0.75, found by 0.25 + 0.50 16. yes, no 17. P(A or B) = P(A) + P(B) P(A and B) 0.30 0.20 0.15 0.35 - = + - = 18. P(X or Y) = P(X) + P(Y) P(X and Y) 0.55 0.35 0.20 0.70 - = + - = 19. When two events are mutually exclusive it means that if one occurs the other event cannot not occur, Therefore, the probability of their joint occurrence is zero. 20. P(H or M) = P(H) + P(M) P(H and M) 0.60 0.70 0.50 0.80 - = + - = 21. a. 0.65, found by 0.35 + 0.40 – 0.10 b. A joint probability c. No, an executive might read more than one magazine 22. a. 0.55, found by 0.50 + 0.40 – 0.35 Chapter 5 48
b. Joint probability c. No, a vacationer can visit both attractions 23.

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