OM HW5

# OM HW5 - Homework 5 Problem 1(7 a Lq = ^2 4.166666667...

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Homework 5 Problem 1 (7) = λ 10 customers / hour = μ 12 customerrs / hour a) Lq = ^2 / ( *( - )) λ μ μ λ 4.17 customers b) Ls = / ( - ) λ μ λ 5 customers c) Wq= Lq / λ 0.42 hours 2 (21) One Worker = λ 2 = μ 2 Dowtime \$= \$40 Ls= /( - ) λ μ λ #DIV/0! NOT Feasible Two Workers = λ 2 = μ 3 Dowtime \$= \$40 Labor/hour \$20 Ls= /( - ) λ μ λ 2 average in system \$40 *2 + \$20*2 \$120 Three Workers = λ 2 = μ 4 Dowtime \$= \$40 Labor/hour \$20 Average in System Average in System Downtime Cost

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Homework 5 Ls= /( - ) λ μ λ 1 average in system \$40 + \$20*3 \$100 <BEST ALTERNATIVE 3 a) = λ 18 = μ 30 Lq = ^2 / ( *( - )) λ μ μ λ 0.9 customers Wq= Lq / λ 0.05 hours b) = λ 36 = μ 51 Lq = ^2 / ( *( - )) λ μ μ λ 1.694 customers Wq= Lq / λ 0.047 hours The consultant is correct (given a .003 margin 4) Model 1 (M/M/1 Queue): Single server, Infinite population, Poisson arrivals, FCFS, Exponential service time, Unlimited queue length

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OM HW5 - Homework 5 Problem 1(7 a Lq = ^2 4.166666667...

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