Job's Method

Job's Method - Total Volume = 0.00600 L = Volume of CuSO4 x...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
# Moles of Reagent 2 Absorbancy 0.000000 1.200 0.000005 1.254 0.000010 1.250 0.000015 1.077 0.000020 1.060 0.000025 0.974 0.000030 0.843 0.000035 0.734 0.000040 0.617 0.000045 0.456 0.000050 0.313 0.000060 0.000
Background image of page 2
Calculations #mole of reagent 2 = (intercept 2 - intercept 1) / l(slope 1-slope 2)l #mole of reagent 2 = 0.3412 / 29636 #mole of reagent 2 = 1.151 x 10^ -5
Background image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Total Volume = 0.00600 L = Volume of CuSO4 x 5H2O + H4EDTA V of CuSO4 x 5H2O = 0.00600 L - 0.001151L = 0.004848 L # mol of reagent 1 = M x Volume of reagent 1 #mol of reagent 1 = 5.0x10^ -3 M x 0.004848 L #mol of reagent 1 = 2.424x10^ -5 moles n = 2.424x10^ -5 moles / 1.1515x10^ -5 moles n = 2:1...
View Full Document

This note was uploaded on 04/18/2008 for the course CHEM 102 taught by Professor Haworth during the Spring '08 term at Marquette.

Page1 / 3

Job's Method - Total Volume = 0.00600 L = Volume of CuSO4 x...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online