Job's Method

# Job's Method - Total Volume = 0.00600 L = Volume of CuSO4 x...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
# Moles of Reagent 2 Absorbancy 0.000000 1.200 0.000005 1.254 0.000010 1.250 0.000015 1.077 0.000020 1.060 0.000025 0.974 0.000030 0.843 0.000035 0.734 0.000040 0.617 0.000045 0.456 0.000050 0.313 0.000060 0.000
Calculations #mole of reagent 2 = (intercept 2 - intercept 1) / l(slope 1-slope 2)l #mole of reagent 2 = 0.3412 / 29636 #mole of reagent 2 = 1.151 x 10^ -5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Total Volume = 0.00600 L = Volume of CuSO4 x 5H2O + H4EDTA V of CuSO4 x 5H2O = 0.00600 L - 0.001151L = 0.004848 L # mol of reagent 1 = M x Volume of reagent 1 #mol of reagent 1 = 5.0x10^ -3 M x 0.004848 L #mol of reagent 1 = 2.424x10^ -5 moles n = 2.424x10^ -5 moles / 1.1515x10^ -5 moles n = 2:1...
View Full Document

## This note was uploaded on 04/18/2008 for the course CHEM 102 taught by Professor Haworth during the Spring '08 term at Marquette.

### Page1 / 3

Job's Method - Total Volume = 0.00600 L = Volume of CuSO4 x...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online