hw8Spring08AnswersRevB - 60 XBAR CHART LCL=9.933 CL=10...

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STAT301T HOMEWORK 8 ANSWERS Page Exercise Points Special Instructions Control Chart Questions: #1 If process mean is supposed to be 10, the process sigma is .05 and the sample size = 5 calculate the LCL, CL and UCL for: 4 4 4 #2 If process mean is supposed to be 10, process sigma is unknown, RBAR = 0.12 and n=5, calculate the LCL, CL AND UCL for: 4 4 4 #3 If process mean is supposed to be 10, SBAR = .048 and n=9 calculate the LCL, CL AND UCL for: 4 4 4 Process Capability Questions: #1 If customer's tolerance = 1.534 to 1.549, producer's n=5 and RBAR = .005 5 5 5 c) Is the producer capable of meeting the customer's tolerance? #2 In above question, if producer's process mean = 1.540 5 4 b) Will all of the producer's parts meet the customer's tolerance?
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Unformatted text preview: 60 XBAR CHART LCL=9.933 CL=10 UCL=10.067 RANGE CHART LCL=0 CL=.1163 UCL=.2459 STD DEV CHART LCL=0 CL=.047 UCL=.0982 XBAR CHART LCL=9.931 CL=10 UCL=10.069 RANGE CHART LCL=0 CL=.12 UCL=.2537 Also calculate an estimate of the process sigma using RBAR/d2 Ans=.0516 XBAR CHART LCL=9.950 CL=10 UCL=10.0495 STD DEV CHART LCL=.0115 CL=.048 UCL=.0845 Also calculate an estimate of the process sigma using SBAR/c4 Ans=.0495 a) Calculate an estimate of the process sigma. Ans = .00215 b) calculate the producer's Cp Ans = 1.16 Why or why not? Ans: Yes because the Cp is > 1.0 a) calculate the producer's Cpk. Ans = 0.93 Why or why not? Ans: No because the Cpk is < 1.0...
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This homework help was uploaded on 04/18/2008 for the course STAT 301T taught by Professor Calver during the Fall '08 term at Purdue University-West Lafayette.

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