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Unformatted text preview: i = =15A 6 30 i = =10A 3 30 i = i = 5A 6 ECE 201 Circuit Theory I 4 Find the response to the current source 3 3 3 4 4 3 4 3 4 v v v  v + + = 0 3 6 2 v  v v + +12 = 0 2 2 v = 12V v = 24V " 3 1 " 3 2 " 3 4 3 " 4 4v 12 i = = = 2A 6 6 v12 i = = = 4A 3 3 v  v12 24 i = = = 6A 2 2 v24 i = = = 6A 4 4 i 1 ” i 2 ” i 3 ” i 4 ” v 3 v 4 R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm I 12 A ECE 201 Circuit Theory I 5 Find the branch currents by adding the results due to each source ' " 1 1 1 ' " 2 2 2 ' " 3 3 3 ' " 4 4 4 i = i +i =15+2 =17A i = i +i =10 4 = 6A i = i +i = 5+6 =11A i = i +i = 5 6 = 1A V 120 V R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm I 12 A i 1 i 2 i 3 i 4...
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 Spring '08
 Helgeland
 The Circuit, Jaguar Racing, Thévenin's theorem, Voltage source, Norton's theorem, Current Source

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