Superposition Powerpoint Notes

# Superposition Powerpoint Notes - i = =15A 6 30 i = =10A 3...

This preview shows pages 1–5. Sign up to view the full content.

ECE 201 Circuit Theory I 1 Superposition Principle of “Superposition” When a linear circuit is excited by more than one independent source of energy, the total response is the sum of the responses to each source acting individually. To find the response due to each independent source suppress voltage sources by replacing them with short circuits (V=0). suppress current sources by replacing them with open circuits (I=0).

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
ECE 201 Circuit Theory I 2 Example, page 130 of the text Find the branch currents in the circuit shown. V 120 V R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm I 12 A i 1 i 2 i 3 i 4
ECE 201 Circuit Theory I 3 Find the response to the voltage source V 120 V R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm i 1 i 2 i 3 i 4 v 1 1 1 1 1 ' 1 ' 2 ' ' 3 4 v -120 v v + + = 0 6 3 2+ 4 v = 30V 120-30

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: i = =15A 6 30 i = =10A 3 30 i = i = 5A 6 ECE 201 Circuit Theory I 4 Find the response to the current source 3 3 3 4 4 3 4 3 4 v v v - v + + = 0 3 6 2 v - v v + +12 = 0 2 2 v = -12V v = -24V " 3 1 " 3 2 " 3 4 3 " 4 4-v 12 i = = = 2A 6 6 v-12 i = = = -4A 3 3 v - v-12- -24 i = = = 6A 2 2 v-24 i = = = -6A 4 4 i 1 ” i 2 ” i 3 ” i 4 ” v 3 v 4 R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm I 12 A ECE 201 Circuit Theory I 5 Find the branch currents by adding the results due to each source ' " 1 1 1 ' " 2 2 2 ' " 3 3 3 ' " 4 4 4 i = i +i =15+2 =17A i = i +i =10- 4 = 6A i = i +i = 5+6 =11A i = i +i = 5- 6 = -1A V 120 V R1 6 Ohm R2 3 Ohm R3 2 Ohm R4 4 Ohm I 12 A i 1 i 2 i 3 i 4...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern