# hw10a - EE 302 HW 10 solutions Chapter 5, Problem 9....

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EE 302 HW 10 solutions 1 Chapter 5, Problem 9. Determine v o for each of the op amp circuits in Fig. 5.48. Chapter 5, Solution 9. (a) Let v a and v b be respectively the voltages at the inverting and noninverting terminals of the op amp v a = v b = 4V At the inverting terminal, 1mA = k 2 v 4 0 v 0 = 2V Since v a = v b = 3V, -v b + 1 + v o = 0 v o = v b - 1 = 2V (b) + v b - + - 1V + v o - Figure 5.48 for Prob. 5.9

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EE 302 HW 10 solutions 2 Chapter 5, Problem 11. Find v o and i o in the circuit in Fig. 5.50. Chapter 5, Solution 11. v b = V 2 ) 3 ( 5 10 10 = + At node a, 8 v v 2 v 3 o a a = 12 = 5v a – v o But v a = v b = 2V, 12 = 10 – v o v o = –2V –i o = mA 1 4 2 8 2 2 4 v 0 8 v v o o a = + + = + i o = –1mA Figure 5.50 for Prob. 5.11 i o + 10 k Ω + v o 4 k Ω 2 k Ω 5 k Ω 3 V + 8 k Ω a b
EE 302 HW 10 solutions 3 Chapter 5, Problem 13. Find v o and i o in the circuit of Fig. 5.52. Chapter 5, Solution 13.

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## This note was uploaded on 04/25/2008 for the course ECE 302 taught by Professor Preston during the Spring '08 term at University of Texas at Austin.

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hw10a - EE 302 HW 10 solutions Chapter 5, Problem 9....

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