7inclass - A photon has a frequency of 6.0 x 104 Hz....

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λ x ν = c λ = c/ ν λ = 3.00 x 10 8 m/s / 6.0 x 10 4 Hz λ = 5.0 x 10 3 m A photon has a frequency of 6.0 x 10 4 Hz. Convert this frequency into wavelength (nm). Does this frequency fall in the visible region? λ = 5.0 x 10 12 nm λ ν 7.1 See page 270, 273
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E = h x ν E = 6.63 x 10 -34 (J s) x 3.00 x 10 8 (m/s) / 0.154 x 10 -9 (m) E = 1.29 x 10 -15 J E = h x c / λ 7.2 When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the photons if the wavelength of the X rays is 0.154 nm.
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E photon = 2.18 x 10 -18 J x (1/25 - 1/9) E photon = E = -1.55 x 10 -19 J λ = 6.63 x 10 -34 (J•s) x 3.00 x 10 8 (m/s)/1.55 x 10 -19 J λ = 1280 nm Calculate the wavelength (in nm) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 state to the n = 3 state. E photon = h x c / λ λ = h x c / E photon i f E = R H ( ) 1 n 2 1 n 2 E photon = 7.3 See page 278
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λ = h/mu λ = 6.63 x 10 -34 / (2.5 x 10 -3 x 15.6) λ = 1.7 x 10 -32 m = 1.7 x 10 -23 nm What is the de Broglie wavelength (in nm)
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This note was uploaded on 04/25/2008 for the course CHEM 1A taught by Professor Tobias during the Fall '01 term at UC Irvine.

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7inclass - A photon has a frequency of 6.0 x 104 Hz....

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