12 - FINAL EXAMINATION OF SPRING SEMESTER 2006 Physics...

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Unformatted text preview: FINAL EXAMINATION OF SPRING SEMESTER 2006 Physics 2211E Test Form 651 Name________________ Test Form = 3-digit number at the top of the first page of this test. Student Number = Your full 9-digit GTID# (Georgia Tech ID number) 1.Print your name, test form number and student number in the section of the answer card labeled STUDENT IDENTIFICATION. 2.Bubble in your test form number in columns 1-3, skip column 4, and bubble in your student number in columns 5-13. 3.For each question, select the answer most nearly correct, circle this answer on your test, and bubble it in on your answer card. Do not put any extra marks on the card. There are 18 problems. The total score is 180, for 10 points each. Equation sheet is attached. Problem 1 : A vector A is added to B = 6i - 8j. The resultant vector is in the positive x direction and has a magnitude equal to A. What is the magnitude of A? (a) 11 (b) 5.1 (c) 7.1 (d) 8.3 (e) 10 A = Ax i + Ay j Ay 8 = 0 Ay = 8 Ax ^2 + 8 ^2 = (Ax + 6) ^2 Ax = 7/3 A^2 = (7/3)^2 + 8^2 A = 8.3 Problem 2 : Two objects begin to free fall from rest from the same point 2.0 s apart. How long after the FIRST OBJECT begins to fall will the two objects be 40 meters apart (let g = 10 m/s)? (a)4.0 s (b)1.0 s (c)3.0 s (d)2.0 s (e)0 s S1 S2 = 40 0.5 g t^2 0.5 g (t-2)^2 = 40 5 t^2 5 (t-2)^2 = 40 t^2 t^2 + 4t 4 = 8 4t = 12 t = 3 Problem 3 : At t = 0, a particle leaves the origin with a velocity of 12 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0 i 4.0 j) m/s 2 . At the instant the particle moves back across the x axis (y = 0), what is the speed of the particle? (a)17 m/s (b)16 m/s (c)18 m/s (d)14 m/s (e)None of the above Sy = 12 * t 0.5 * 4 * t^2 = 0 t =6 s vy = vy 0 = 12 m/s vx = 2 t = 12 v = 17 m/s Problem 4: During volcanic eruptions, chunks of rock are blasted out of the volcano. At what initial speed must a block be ejected 45 above the horizontal so as to land at a point displaced 2.8 km below and 8.6 km horizontally from the initial point? (a) 0.28 km/s (b) 0.25 km/s (c) 0.18 km/s (d) 0.22 km/s (e) None of the other choices. Sy = vy * t - .5 * 9.8 * t ^2 = - 2800 Sx = vx * t = vy * t = 8600 t = 48.2 s vx = vy = 178.3 m/s v = 252 m/s = 0.25 km/s Problem 5 : A uniform 3.0-kg sphere rests on two flat frictionless surfaces as shown in the figure. What is the magnitude of the force of figure....
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This note was uploaded on 04/27/2008 for the course PHYSICS 2211 taught by Professor Uzer during the Fall '08 term at Georgia Institute of Technology.

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12 - FINAL EXAMINATION OF SPRING SEMESTER 2006 Physics...

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