MATH 2300 Exam 1 (Fall 2006)

# MATH 2300 Exam 1 (Fall 2006) - MATH 2300 CALCULUS 2 MIDTERM...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: MATH 2300: CALCULUS 2 September 20, 2006 MIDTERM 1 I have neither given nor received aid on this exam. Name: 001 J. Newhall ........... (9am) 002 S. Preston ...........(10am) 003 K. Kearnes .......... (11am) 004 S. Preston ...........(12pm) 005 J. Wiscons ............ (2pm) If you have a question raise your hand and remain seated. In order to receive full credit your answer must be complete , legible and correct . Show all of your work, and give adequate explanations. Some useful formulas: Z √ u 2 + 1 du = u 2 √ u 2 + 1 + 1 2 ln ( u + √ u 2 + 1 ) + C Z √ u 2- 1 du = u 2 √ u 2- 1- 1 2 ln ( u + √ u 2- 1 ) + C DO NOT WRITE IN THIS BOX! Problem Points Score 1 30 pts 2 30 pts 3 30 pts 4 30 pts 5 30 pts 6 30 pts 7 30 pts 8 30 pts TOTAL 240 pts 1. (30 points) If Z 1 f ( x ) dx = 12, then what is Z 1 xf ( x 2 ) dx ? If u = x 2 , then du = 2 x dx , so Z 1 xf ( x 2 ) dx = 1 2 Z 1 f ( x 2 ) 2 x dx = 1 2 Z 1 f ( u ) du = 1 2 (12) = 6 . 2. (30 points) Starting with the integral definition of the logarithm function, which is (i) ln( x ) = Z x 1...
View Full Document

{[ snackBarMessage ]}

### Page1 / 5

MATH 2300 Exam 1 (Fall 2006) - MATH 2300 CALCULUS 2 MIDTERM...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online