the discriminant - Algebra one semester one unit five...

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Algebra one, semester one, unit five, assignment: the discriminant For each problem I found out what a, b, and c were. I filled in the format with the numbers that equaled a, b and c. I multiplied the exponent first, then four times a and c. The final thin I did was subtract the numbers and write how many real number solutions there were for the problem. B^2-4*a*c X^2+6x-3=0 A=1 b=6 c=-3 6^2-4*1*-3 36-4*1*-3 48 There are two real number solutions 3x^2+2x+1=0 A=3 b=2 c=1 2^2-4*3*1 4-4*3*1 -8 There are no real number solutions X^2+4x+4=0 A=1 b=4 c=4 4^2-4*1*4 16-4*1*4 0 There is one real number solution 5x^2+x=4

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