100%(22)22 out of 22 people found this document helpful
This preview shows page 1 - 3 out of 3 pages.
Algebra one, semester one, unit five, assignment: find maximum and minimum Y=-x^2+50x+10To know if a vertex is a maximum or a minimum you look at whether the x^2 term is positive or negative. Negative is maximum and positive is minimum. Since the number that fills the place is negative the vertex it maximum.To find the x coordinate of the vertex you use the formulaX=-b/2aA=-1 b=50X=-50÷2*-1X=-50÷-2X=25To find the y coordinate of the vertex plug the number found from the x coordinate into the function Y=25^2+50*25+10Y=625+1250+10Y= 1885(25,1885)For this situation the vertex represents the characters path. X is twenty five and that is the time in seconds it takes the character to move across one parabolic path. Y is one thousand eight hundred eighty five and that is the height of the character in pixels.Y=2x^2-20x+100To know if a vertex is a maximum or minimum you look at whether the x^2 term is positive or negative. Negative is
maximum and positive is minimum. Since the number that fills the x^2 place is a positive number the vertex is minimum.