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Distance and direction - Algebra one semester one unit...

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Algebra one, semester one, unit two, assignment: distance and directions Scenario one The relative distance is 3-5+13=11 miles east The total distance is 3+5+13=21 miles total (40mi/gal)X (1/4gal) =10 mi There is enough gas to go ten miles so there is not enough gas for this trip Scenario two The relative distance is 10-15+5=10 The total distance is 10+15+5=30 33-30=3 There is enough gas for thirty three miles so there is enough gas for the trip Scenario three The relative distance is 15-15+23-13=7 The total distance is 15+15+23+13=65 20X5=100-65=35 There is enough gas for one hundred miles so there is enough gas for the trip
Scenario four A truck will drive 2 miles west 6miles east and 10 miles west. The truck gets 36 miles per gallon and has 2 and 1/2 gallons. The relative distance is 2-6+10=14 The total distance is 2+6+10=18 36X2=72 36÷2=18 There is enough gas to go 90 miles so there is enough gas for the trip Scenario five A suv will drive 5 miles south 2 miles north and 100 miles south. The suv gets 20 miles per gallon and there are 8 gallons of gas The relative distance is 5-2+100=103 The total distance is 5+2+100=107 8X20=160 There is enough gas to go 160 miles so there is enough gas for the trip
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Unformatted text preview:Scenario four A truck will drive 2 miles west 6miles east and 10 miles west. The truck gets 36 miles per gallon and has 2 and 1/2 gallons. The relative distance is 2-6+10=14 The total distance is 2+6+10=18 36X2=72 36÷2=18 There is enough gas to go 90 miles so there is enough gas for the trip Scenario five A suv will drive 5 miles south 2 miles north and 100 miles south. The suv gets 20 miles per gallon and there are 8 gallons of gas The relative distance is 5-2+100=103 The total distance is 5+2+100=107 8X20=160 There is enough gas to go 160 miles so there is enough gas for the trip