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PHY 205
Sections II
Lab: 6
October 4, 05
Coefficient of Kinetic Friction
Bijaya Singh Thapa
Abstract:
For the motion with a constant velocity (i.e. no acceleration) up the incline (i.e. no
acceleration), the free body diagrams for the block B and the descending mass D yield
the following equations,
T
1
–f –Q’ = 0
M
D
g – T1 = 0
Here W is the component of the weight of block B parallel to the incline. Combing
both equations we obtain
M
D
g –f – W’ = 0
(Eq. 1)
For a motion with a constant velocity down the incline, the free body diagrams for the
block B and the ascending mass A yield the following equations,
W’ – T
2
–f = 0
M
D
g –T
2
= 0
Combing both equations we obtain
W’ – T
2
–f = 0
(Eq. 2)
Subtracting Eq. (1) from Eq. (2) we could express the force W’ in terms of m
D
and
m
A
.
W’ = ½ (m
D
+ m
A
) g
(Eq. 3)
Adding Eq. (1) and Eq. (2) we ger
f=1/2 (m
D
–m
A
) g
(Eq. 4)
On the other hand, the force of friction could be written as
f = µ
k
m
B
g cosθ
(Eq. 5)
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 Spring '08
 Mishra
 Acceleration, Friction

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