Lab6.rtf

# Lab6.rtf - PHY 205 Sections II Lab 6 October 4 05...

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PHY 205 Sections II Lab: 6 October 4, 05 Coefficient of Kinetic Friction Bijaya Singh Thapa Abstract: For the motion with a constant velocity (i.e. no acceleration) up the incline (i.e. no acceleration), the free body diagrams for the block B and the descending mass D yield the following equations, T 1 –f –Q’ = 0 M D g – T1 = 0 Here W is the component of the weight of block B parallel to the incline. Combing both equations we obtain M D g –f – W’ = 0 (Eq. 1) For a motion with a constant velocity down the incline, the free body diagrams for the block B and the ascending mass A yield the following equations, W’ – T 2 –f = 0 M D g –T 2 = 0 Combing both equations we obtain W’ – T 2 –f = 0 (Eq. 2) Subtracting Eq. (1) from Eq. (2) we could express the force W’ in terms of m D and m A . W’ = ½ (m D + m A ) g (Eq. 3) Adding Eq. (1) and Eq. (2) we ger f=1/2 (m D –m A ) g (Eq. 4) On the other hand, the force of friction could be written as f = µ k m B g cosθ (Eq. 5)

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## This note was uploaded on 04/26/2008 for the course PHYS 205` taught by Professor Mishra during the Spring '08 term at South Carolina.

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Lab6.rtf - PHY 205 Sections II Lab 6 October 4 05...

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