# GraphicalRatesMethod2-Key-Chem110.pdf - 1. Based on the...

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1.Based on the following experimental data, determine the rate law (including the rate constant) for the reaction A --> 2C.[A] (M)Time (s)0.500.46500.411000.371500.332000.292500.243000.203500.164000.114500.07500ln[A]Time (s)-0.69314720-0.783071950-0.8818893100-0.9915532150-1.1147417200-1.2552661250-1.4188176300-1.6144505350-1.8578993400-2.1803675450-2.659265001/[A] (M-1)Time (s)202.18818381502.415458941002.695417791503.048780492003.508771932504.13223143005.025125633506.410256414008.8495575245014.2857143500Concentration vs. time gives straight lineâ€¦Rate = 8.60x10-4Ms-1(A is zero order)Concentration vs. Timey = -0.000860x + 0.500000R2= 1.00000000.10.20.30.40.50.60100200300400500600Time (s)[A] (M)ln(Concentration) vs. Timey = -0.00362x - 0.50015R2= 0.93044-3-2.5-2-1.5-1-0.500100200300400500600Time (s)ln[A]1/Concentration vs. Timey = 0.0192x + 0.1508R2= 0.73370510150100200300400500600Time (s)1/[A] (M-1)
2.Based on the following experimental data, determine the rate law (including the rate constant) for the reaction A --> B + C.[A] (M)Time (s)0.500.49500.471000.461500.452000.432500.423000.413500.404000.394500.38500ln[A]Time (s)-0.69314720-0.723433950-0.7528302100-0.781387150-0.8091509200-0.8361647250-0.8624679300-0.888097350-0.9130856400-0.937465450-0.96126415001/[A] (M-1)Time (s)202.0615502.1231002.18451502.2462002.30752502.3693002.43053502.4924002.55354502.6155001/concentration vs. time gives straight lineâ€¦Rate = 1.23x10-3M-1s-1[A]2(A is second order)Concentration vs. Timey = -0.0002x + 0.495R2= 0.994400.10.20.30.40.50.60100200300400500600Time (s)[A] (M)ln(Concentration) vs. Timey = -0.0005x - 0.6988R2= 0.9986-1.2-1-0.8-0.6-0.4-0.200100200300400500600Time (s)ln[A]1/Concentration vs. Timey = 38.141x + 60.821R2= 0.7337010020030040050060070002468
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Term
Spring
Professor
KAUTZ
Tags
Harshad number, Hebrew numerals, Rate equation