SampleTest4Soln

SampleTest4Soln - MEN] Testflfi Falllflflfi Name...

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Unformatted text preview: MEN] Testflfi Falllflflfi Name {print}: ___ __ Section 1 . (31] {its} Twc spheres are translating with the velocities shown immediately before they collide. The weights are shown. The coefficient of restitution between the [we materials is 11.60. The contact surfaces may he considered In be frictionless. Find the velocity vectors of each sphere immediately after the impact is complete. Find the percentage of less in kinetic energy,r due to the n mEEt' pwluffcw FINE-0mm) Mir # (p 412%] m f” it: P“ . D i}: : 3L : mAMLFLFEML 1r s r— em “Dim. caste —(Hq«) _________________/ MWM‘lerfirzm‘j‘fi? Cams. I II “11‘” + m '19 [Yr-9N: : “in Threat. “L Weigh L ME 201 2. Test #5 Fall 2006 Name [print]: Section {30 pin] The system rotates in a vertical plane and is at rent in the 1.i'tzrlictzll position whcn 19= 90°. The I2-ih nonuniform bar SA has a center of gravin at G as shown and n til-in radius ofgyrutiun about an axis at G pcrpeudicular to the plant: (if mention. The pin hearing at U is frictinnless. The linear spring is unstretched in the initial at rest pmition. The spring has a stiffness 01'3- ibiin, nr 35 lhifi. A constant couple M is applied tr.- caust: the system to rotate: clockwise. Find the ntngnitudn 0|" M such that when the bar is horizontal {t9= 0°} the angular speed Will he 4 radfscc. CED—wig) ME 3U] 'l'esl #5 Fall 1006 Name (prim): 3. (41) p15] The three hats can rotate about the x-axis en a 05"“ n a A] frictionless hearing. The two bars A are ennneeted so a d" 5: tr.- mnve tngether as one. Each of the two 13615 A has a ' mass euth} kg and radius of gyratien about a parallel x— axis through their CG of 20!] mm. The shorter hat- B has a mass of 8 kg and radius efgyratifln about :1 paIallel x- axis through its CG of ISI‘JI mm. 'Ihe respective CG locations are shown. The bars are at real when her B ifi released fmrn its original horizontal position as sheen. When her B is 1iret'tieal, the neteh at C 011 bar B impacts the connecting pin between the two A bars and attaches tn the pin If i _e., the eacifieiei-it ul' restitut-Enn is zero]. After impact the three bars mnve as. one. Calculate the _ - - : maximum angle 6' In which they rotate as they come to a @QJ‘) slop fur an instant. £672...“ 3(3):: '5’"? kfl'“ f :2(Le)(,tjz=i.to leg?“ (Ta IT 'l U: 4;; L __- it. 1 _t "‘ __. ctr» +§fa.k’i)(.ie) 2.13 mg: +ée’(.iatmm) We?) _ ~ - " ‘7‘?" ' ' five @xfi we» WWW-we A (ta. tee-'- almflfig We?“ xi— 0 1' IMFHEIU‘C L_L_____L ' __L fill—lat 7; H793, H03: Lia-g. Logefil lgE/erfimfr _3'1 a} : TEE-3:- . _ .- i’ A A TIE-at. gin—ff Q: I”— — ngi‘rfi'figlfii +{i'lgjjfig #lfdméél) w- *FKr-vmyrfi—wefiitfi ._ ____———'_"fi_A‘—"j L ECle LES—i; n.6,," -Z'Sl We. Hal: “ , 52?— la l’z‘l'l’“ 555* _ _ _ _ ______.- = o . '____ '5:- Eiflih efijd—fif/fi; “52:43 “33. +3) helm areal D . — fl - “a I ’3 “ has: (0-H “*0 awnmsmom.Tl+t=wmtwi /:-_;_;._ _____ A . KHG; .5 3e: LJ; t8; . _- 3,571 H.- :— rte—3.6m L43 {Han lib-Ing '1. ’T' r: 2 Ifig.) + éMUE? = LEG-sf: H-M UH? = -€(€,KI)C-EKJCI"HL€3) — 40(q.m;.cxzr)(:- me) :: -HLZ} (1— c-m—Efi) LEG-é} Hill-LlClnmE-D :c: a 11 no.3“; “L13. (9 : 311$" d = 100 15 mm As a practice problem on the last material we covered, consider the Geneva mechanism in problem 16.49. Disk D drives the mechanism and rotates at a constant speed of 2 rad/sec while the Geneva wheel accelerates and decelerates. The pins that engage the Geneva wheel are firmly attached to disk D. Find the angular speed of the Geneva wheel when 9 = 0 and when 6 I 30. Also when 9 = 30, find the angular acceleration of the Geneva wheel and the force the pin puts on the slot of the Geneva wheel. Assume all friction is negligible and the Geneva wheel has a mass of 3 kg and a radius of gyration of 75mm. Make sure you clearly identify to which body, where, and the alignment of the rotating coordinate system. Also, think about other things like u the moment required to drive the disk D at a constant speed through out a complete 360 degree cycle 0 how the speed and acceleration of the Geneva wheel vary through its cycle of motion 0 how you could change the time between motion cycles of the Geneva wheel 0 how a constant applied moment drivin disk D would affect the motion of the Geneva wheel. : 1: will {HEAL xyx$jm is rlze Gem WM) afil's Levi-bf all! Misoupcné-alnj sic—l9". A :2 o 4. ans/Al +QILAk)?‘-(”,574}8 1‘) - {,KJQS)L(-.o7443 u“) +2 (sugxfiméfi 2(qu +.o4945)’f + (10741357: * 3”“)3 mm+ DMQJV "tag-F‘s f: , $409+ : (am1.04‘?2P£)(,7583)+(—,o7fixif, $1125)(«,a,757) ..,5qz7 = 33%”? a?“ + @590 JLA A 3‘; ,L0 = (arm «044745)(4ny9 +(-,o7‘4»1$jz,,A «3116)(7325) ,gqéé = -‘b73~‘1 arm - .05+§‘z SLA ‘. FWLQO'W C'Iam [AM n£ 9:30: IA:SC°75) Ell/6375’ — ) ( I} @5133} "\ ') 2M 3 - fi(.07418) =Colros’7r)(a.333) F“: _. 2.125 é)4z'”° = Z- N M 2 (ALsz 9=r~4§ flag-"JO +JiHA:MM-7c+ Wham 6‘le «(L/4:0 + JLA:W_ 90 FM Mme/5M6;er (“mat—Ls“- (gr FD (7‘1 opléLb 61/59 wmé; (Prim‘uo MM 0% b Mus/flake m7 H: my? ops/“IR sfeeégwfil a; U96 flower Mjacgi‘r‘j 6'35 W b Lang->4” K4».th @awm ad».er 070-135 ...
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SampleTest4Soln - MEN] Testflfi Falllflflfi Name...

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