{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW29soln

# HW29soln - 16.10 The l-lb collar A is initiallyr at rest in...

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 16.10 The l-lb collar A is initiallyr at rest in thc position shown on the smooth horizontal bar. At f= i}. a Force . __ "L . _ _|_ 1 I 1‘5“ + Ini-I In: I “h iis applied to the collar, causing ill to slidc along the har.W11alis lhc vclociiy oithc collar at i = 2 S? 'III' if" :0 4. lb, mm. ..=_L 1, ‘91, 3'31,”— ..:_ L U1. 16.14 The iﬂ-kg box starts from rest and is subjected to the horizontal force described in the graph. The coefﬁcients of ﬁction between the box and the surface are p1,, = pk = [1.2. Determine how fast the box is moving att= [25. Ref 1244? um mar. p“ H. HN'I £731 M .2. etitf‘i‘j Wuhan F7F: 1 FF ‘lCﬂOﬂH'EH pow/t, = [1 can “41!". Cl _‘ MT}; )3» + L's-ﬂ] on = 1:1» ' d—ﬂ'f‘ﬁb {-I qud + F—e o + germ-W445?) + SD (4') + {199(4) "Galaozrlsﬁ -— 1c: vL "We '-’* {\$5.01 hygﬂ a Iii-.52 A bullet with a mass ofﬂﬁ grams is moving horieootaIl},r with velocity v and strikes a S-kg block of wood. becoming embedded in it. After the impact1 the bullet and block slide 24 mm across the ﬂoor. The coefﬁcient ofkinetie friction between the block and the ﬂoor ism = 0.4. Determine the 1velocity v. we? Wit tee sgr eaché-n ML? .walse Mom—Em- on. W, WE. w ELSMM imbetgwf ﬁmﬁT—m. trek? ‘F-“HUQP. fig-.37?- Wﬁﬂqgﬂ I . . , . .51" L99; Invtif-{Tjﬁ‘tﬂi 53.99““?ij [gaff C1. Mglgﬂnkﬂg. ‘9 IX: h bled- £9):- qﬁ r‘arm ﬁguragy'ftrg EMMmM/‘r'fml +£— WWLQ PWLa Min-«IL; : j :3, eff = .0429: Wu) _, -°“3”='__‘-’"A. -M.{pl AT = S,oo 5r. '3':- 'i. m —- .md—I IL. 11;: 5.1" +1.94“ M 15va ULHOMm mm: “ﬁrm \$.00“ Vm=(903-.S‘ infant-1.35" "' t5"! 7- ".Wl =Gai'.¢|- :: 1- 0.“! 90 2,055 :EB-Dl. : 1‘- 4'.ng :2an =55“; ‘-'- + 6’1?“ : ”0 =93: : + 4- z, -:. L235: no 1}" z. = a ﬁn 99 Tic/To MWK-P indeﬁn- ‘Ervu. (UHF;- mMﬂkﬁ-réﬂ L1,, Mt'mmtmt. éd' A?“ km W m \$012250" f6». FwdirfFﬂ/‘Lt Mm Mrytégﬁmf 1’ ”5%.- hem» in HM far he air-3771‘) cu" Fuli train-r W 2K»! MW Ef— {ﬂ ail-“(’- L'm Riff-fl)- d're-r 2.5.me * I950 An astronaut ﬁres a thruster of his maneuvering unit. exerting a three T= 21:] + t] N. where t is in seconds. The combined mass of the astronaut and his equipment is 122 kg, and the moment of inertia about their center ofmass is 45 kg-mz. Modeling the astronaut and his equipment as a rigid body. use the principle ei‘ tngula: impulse and momentum to determine how long it Lakes for his angular velocity to reneh 0.1 mde’s. 1. 19.51 A. ﬂywheel attached to an electric motor is initially at test. At t = ii, the motor exerts a oouple M: EDUe'OJ'N-m on the ﬂywheel. The moment of inertia of the flywheel is ill leg-mg. {a} 1|What is the ﬂywheel's angular velocity at t = H} a? {b} What maximum angular velocity will the ﬂywheel attain“:I ...
View Full Document

{[ snackBarMessage ]}

### Page1 / 6

HW29soln - 16.10 The l-lb collar A is initiallyr at rest in...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online