HW3soln

HW3soln - H5" saplizum“ I Hw'h w TuhIc-(irmlp I...

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Unformatted text preview: H5" saplizum“ I Hw'h w TuhIc-(irmlp I "3.1 W Rom-1' weighs IIJD lb and ham: 3 weighs 30 1h.Ti1u um: Fficicma affliction between box .4 and the ramp an: ,u‘ = 0.30. and pk = U28- {3} Assuming, Hie boxes are slulic. what is It“: magnitude nl'thq: I‘rictiun force uxcrlcd on huts! by the ramp? (I!) Compare this tn Ilw: upper limit on the Mali: Friction fame to see if the hnxcs an: acluaHysiaLic. aéfiflw Id- H - “OWN n 2' ,4- (q) 1::- FJFTA 7\/,«vr fl Fl: p: n {‘EMCTO xii-EJF-(lé-r 1}. : i 1503: .4 weighs [DU lti1 and flu: coefficients of [ric1iun bchwII hm: .4 and ['11: rump are m - 1130 and m 223. (:I} Fnr what rung: ul'wcights fifth: Imx B will the system remain slationarf? (tr) H‘be B weighs 20% more than the upper limit ynujust found. lind the :ucwluruliuns 01' the boxes and the tension in Ihe cable. The pill Icy mass is nugligihlc, flu: hearing is I'rictinniuss. and 1|“: t'zlhh: (lune: T1131 slrclch. (q) E; an» {{9be A kaLW 23/ ... Lil-— Em? Lmdv‘a; 35%“me fl fL/‘y r00 Fi'w‘i 9'5“? gmi: ., .,.,. Em; w Kayak-aw F = HM e—-—--——— 1° (F 0-1;: Y-_|EJM1L‘:EZ_£FLI§ZQ . I I ’?€’J”';F§ - 5 A wot}!— (F; :4 “Fm-.3; '3 3. ‘FY F, \ H'W-x JIESLAEO to 5"» £— Lflf Z4301m< B 475.618 _ Em“ “w flab 1: it) {2.3 L:|,z(7g.e§)=fii.1s’ 11:. J mm avg?“ :ffiTs/cpca) Sit;be Gag-Ea £919} MAJ-"é 5+L9EL ‘13:: 34"?5fi—lff' 7-: .— fl __|___'__.._.—r"— jb fl __ W MP 32.? W ct. 7’ 113’ W3 G L ' “fix 3: : a—H— :3. } :': The cncl‘ficicnl oft-linen: fricliun hclwccn the lflfl—kg box and the inclined surface is 0.35. in) Determine llu: lunsiun i“ raccussmy In puli the lam: up Ihu surface in n cunslnnl rnlc. {h} ff, ifthe tension is iTIC-rL‘flfiL‘Li by HM. war the mine found in {a}. find the acceleratinn nfihe [um-c. (“fax-i" I KC" 31:". h I. .- -— J I . (a; a: — o C can :56 2061664 '0 i < «t r . .5: f N i mafia“ . ’ i $924 Kl "\flfi‘d MK \fl'” F“ F I _ I ___ __ _- IF’ k£E#f-—H_qfl (#30) 4"?‘315 k1,}? ung — ’51: 431 (cu-Lad) ; 2’ Ell-141...: Lu-c LW Sift? J F ESQ-i“? €15) HI { 1f. _ .. qg, \ \g‘fi FEET-acre: Calla -r-'iL =mm i 1 *1 — f g7 - 30.1qu 03)) — ‘34 (it; ~ I713 :{Q0 1:; "$27,042 1/th _ A «min-1m}.- [link of Jun-mm nulius in :LI1;H.'hI:d In a I'rit'tumlum. pin mppqm .u 4"}. Ha.- dixL n. hdd in Wan: I13: Ihu hulk”: Am‘ in cunnm wilh l1": dial. .1: {I Tim: hydraulic Mlualur HE “cm a tmlimmnl «It'll-N forum-1|“: bake at B. TI“: cwfliuiuflm ul' {I'LL-Hun Psi-hum" llu: did. and III: I'Iruh; :IIE y, -- ".15 and [11 1 0.5 The wuiglux 1.1" F“ and AHF ill": negfligihlt. In] ‘L‘Fltai cwplc .‘H' musl he applied 11.} I11:- \Iu1iuliiif} diak I.u mum: in in ~lul1lu5lip in. Iluu cmlntcrdnckwisc din-Hints? ItI] rifle: i1 :11er slipping. In when value tin-1:5 1h: ruuptu have m be reduced tn Lamar: flu: disk In hump! mulling :II :I cum-null spin-ti? (31 9M 1*: c - 4°” C - 5" - .__'- f £2 (ff-MP1- 1an '" I f \ I" ‘15 I M 1" 1 |Illl - I 1 a II. I “Inning-I] .I.-'.'I'I||" J mm". 1'.“ I I I . _'.v- :mn‘ Ir—““f"__:*l II' I I f ' Ii _1 k _: \__I If "IJ: nun _,_.:*:-E * fl ‘f' (“12.2) f, 1 J+Cx--EC} H4uof a} "3.4 ‘1 The airplanc‘zr: weight is W= 24011 |h_ lls brakes keep the rear wheels luukunl. 'l'hc mel'flcienls of i‘l'iuliun between the mar whch 11nd fin.- runway are m " 0.6 and m- -- {1.5. The I'runt { {nusu} “heel can turn freer and em exerts a negfigihle hurimnml force on the runway. {ah Dem'mlne Ihe horimnla] lhrus: I'orcc T [he plane's pl'npclltr WmIILl hum: I“ generate 10 muss; the run: whack m be on the wry: 1:1"51ippinglsiiding‘g. {b} [I'll-u: thrust is inert-mad jusl laurel} alum-e That value. Le. elm-ugh [u gum plunu muting [rear whccls slidil'qgj~ what i5: Ihc acceleration nl'Zli'm? (a) C W U‘fi'v‘tgfl Jlr" S-{L- {7 ...
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HW3soln - H5&amp;quot; saplizum“ I Hw'h w TuhIc-(irmlp I...

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