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Unformatted text preview: Monday Feb. 12, 2001 EE 381 Last Ft: A 25 KVA, 24001940 V, 60 Hz, 2-winding transformer has the following given: H.V. side: R1 =1.7 ohms, X1= 2.6 ohms; LV. side: R2 = 0.0165 ohm, X2 = 0.0“)“ 1E-
The core 103;]: at réted voltage is 120 watts.
,__————-—'—--...7\
f. 1. Find the %Regulation(neg1ecting the parallel branch) for 5411 load and 0.6 pfladll; O._ fl 2.: ’0 .da-L' ’91
24‘,
£2}: {‘7 J- 0 0/59 x/o—a : 335‘11
39,, ~.—. 2.5 + 0 0234* ’‘0'11 ‘-= 53/4).
I l 25-006 __
Leif-W " ‘5 "' ,2.qu - (’0 4/5 A-
Pymar. . aux—m) = rs
a. '34. JF‘ . ‘r-q o ,v
V, ~— éfirn L; + H0 4/5/‘5-5‘f3 {3 3y +£- I)
. '“h J'
.: "92‘70 a '5 {-—
- - " '4:- + J 5-9-79 r we - Q56 7 ,3 J“
2. Find the efficiency at £4 fill! load and 0.8 power factor lagging.
D . ':
a. ‘1? h
. fl =!___‘5:_QEL_yo.Q -.~ $0.50“ W
2.1. x/ 9 UM
o ‘ LUNA. [(5 a J
/C’¢_H "' ’20 ("I \
5 la.
5. d .7. ’0' [“6 ,4. 5*"
”Lag. 1..
n W . LL ()(aow
’VCO - Mk]: 3 3f *1 23' 7ft“ -
fl” \ c/ / ‘° '
ta; . {~—
4_ a 6 0 G
/{ £{la ‘ [Y .011) ...
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