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210 lab1 - .0416 M H3PO4.0988 M(H3PO4 HCl.0416 M(H3PO4...

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Chem 210 Dr. Baldwin 01A Justin Cann 03/06/06 Experiment 1 Potentiometric Titration of an HCl-H3PO4 Mixture Unknown D Partner: Daniel -
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Standardization of NaOH: .300g( 1 mol/204.23 g) = .001469 mol H+…NaOH / .0098 L = .1499 M NaOH Sample 1 M NaOH: .1499 M NaOH Sample 2 M NaOH: .1530 M NaOH Sample 3 M NaOH: .1538 M NaOH | .1499 - .1530 | / | .1538 - .1499 | = .79 < .94 Not Rejected (.1530 + .1499 + .1538 )/3 = .1522 Average Standard Deviation = ( .00000849 / 3-1)^(1/2) = .002060 RSD = s/average * 100 = .002060/.1522 * 100 = 1.354% Conf. Limit = 4.3 (.002060)/3^(1/2) = .005114 M NaOH average ± Conf. Limit = .152 ± .0051 Concentrations of HCl and H3PO4 in Unknown D: .152 M NaOH(.01625 L NaOH) = mol H3PO4+HCl/(.025 L) … .0988 M H3PO4 + HCl .152 M NaOH(.00685 L NaOH) = mol H3PO4 / .025 L … ..0416 M H3PO4
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Unformatted text preview: .0416 M H3PO4 .0988 M (H3PO4 +HCl) - .0416 M (H3PO4) = .0572 M HCl Titration 1: HCl, .0572 M H3PO4, .0416 M Titration 2: HCl, .0584 M H3PO4, .0410 M Titration 3: HCl, .0575 M H3PO4, .0413 M Average M HCl: .0577 Average M H3PO4: .0413 | .0584 - .0575 | / | .0584 - .0572 | = .75 <.94 Not rejected HCl | .0410 - .0413 | / | .0416 - .0410 | = .5 <.94 Not rejected H3PO4 HCl Standard Deviation = ( .00000078 / 3-1)^(1/2) = .0006244 H3PO4 Standard Deviation = ( .00000018 / 3-1)^(1/2) = .0003 HCl RSD = .0006244/.0577 *100 = 1.08% H3PO4 RSD = .0003/.0413 *100 = .726% Conf. Limit = 4.3 (.0006244)/3^(1/2) = .00155 Conf. Limit = 4.3 (.0003)/3^(1/2) = .000745 M HCl average ± Conf. Limit = .0577 ± .0016 M M H3PO4 average ± Conf. Limit = .0413 ± .00075 M...
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