ME311-HW7 - Homework#7 Solution ME 311-Winter 2016 Due Date...

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Homework #7 Solution ME 311-Winter 2016 Due Date 03/11/2016
1 5.10. Find the fully plastic moment M P and the location of the corresponding neutral axis for the beam section of Figure P5.10, if the uniaxial yield stress is 200 MPa.
2 where y is measured from the bottom of the section. Noting that areas A 3 , A 4 , A 5 are in compression and the others are in tension, equation (5.28) gives M P = 200 × 10 6 × ( 2 × 125 × 22 . 5 + 2 × 18 . 75 × 18 . 125 - 2 × 81 . 25 × 8 . 125 - 125 × 2 . 5 ) × 10 - 9 = 934 Nm .
1 5.29*. A circular ring of radius 200 mm and square cross-section 4 mm × 4 mm is to be manufactured from steel of Young’s modulus E = 200 GPa and tensile yield stress S Y = 200 MPa. 400 π 4 M M (a) 4 400 weld

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