TEST1_2008-soln - v . For mesh 1, 2(i 1 – i 2 ) + 4(i 1...

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Engr 260 -- Circuits & Devices February 20, 2008 Name: ____ SOLUTION ____________ 1. For the circuit shown: a) Find eq R as seen by the voltage source. b) Determine the current I through the voltage source. Req = = + = + + 2 3 ) 3 6 2 ( 4 3 5 Ω I = = = 5 10 q Re 10 2 A 2. For the given circuit, determine the current in the 2- Ω resistor using nodal analysis . 3. Use mesh analysis to find the current in the 4- resistor.
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4. Using nodal analysis , find the voltage 0 v . 5. Use mesh analysis to find the voltage
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Unformatted text preview: v . For mesh 1, 2(i 1 – i 2 ) + 4(i 1 – i 3 ) – 12 = 0 which leads to 3i 1 – i 2 – 2i 3 = 6 (1) For the supermesh, 2(i 2 – i 1 ) + 8i 2 + 2v + 4(i 3 – i 1 ) = 0 But v = 2(i 1 – i 2 ) which leads to -i 1 + 3i 2 + 2i 3 = ( 2 ) For the independent current source, i 3 = 3 + i 2 ( 3 ) Solving (1), (2), and (3), we obtain, i 1 = 3.5 A , i 2 = -0.5 A , i 3 = 2.5 A ....
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This note was uploaded on 04/28/2008 for the course ENGR 260 taught by Professor Enriquez during the Spring '08 term at San Mateo Colleges.

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TEST1_2008-soln - v . For mesh 1, 2(i 1 – i 2 ) + 4(i 1...

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