Solution_Set__1

Solution_Set__1 - $1.00/$1.48 per kilogram = 0.676...

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University of Southern California MASC 110L Problem Set #1 E. Goo Due August 28, 2006 Do the following problems from Chapter 1 in Brown and Holme 1. 1.40 -186 o C + 273.15 = 87.15 K 2. 1.43 a) 6.213x10 1 b) 4.14x10 -4 c) 5.1 x 10 -6 d) 8.71x10 8 e) 9.1x10 3 3. 1.45 a) 3 b) 3 c) 3 d) 2 4. 1.47 a) 34.4 b) 0.48 c) 32 d) 0.012 5. 1.52 Volume = 17 ml – 11.3 ml = 5.7 ml or 5.7 cm 3 Mass = 12.1 g Density = 12.1 g/5.7 cm 3 = 2.1 g/cm 3 6. 1.54 $1.48/8 = $0.185
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Unformatted text preview: $1.00/$1.48 per kilogram = 0.676 kilograms 7. 1.56 A picometer is 1x10-12 meters 148 pm = 1.48x10-10 meters 8. 1.57 a) 3.47 microgram b) 0.273 mL c) 7.25x10-7 s d) 1.3x10-3 km 9. 1.60 92 meters/second x 0.001 kilometers/meters x 3600 seconds/hour = 331.2 kilometers/hour x 0.60 miles/kilometer = 198.7 miles per hour 10. 1.63 3.6 kg x 1000 g/kg x (1/0.87) mL/g x .001 L/mL = 4.1 L...
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This note was uploaded on 02/28/2008 for the course MASC 110L taught by Professor Goo during the Fall '07 term at USC.

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Solution_Set__1 - $1.00/$1.48 per kilogram = 0.676...

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