Tarea4 - MATEMTICAS I MA1015-8 Dr scar Fuentes M fuera de...

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Ejercicio Solución Encuentre el valor de x 1. 27 3 3 7 = x 4/3 2. x x 2 7 3 125 5 = -7/3 Si es que existe, obtenga la función inversa de la funciones 3 a1 9 3. 3 ) 2 ( ) ( 2 = x x f x x f + + = 3 2 ) ( 1 4. 2 5 3 1 2 ) ( + + = x x x f 8 3 9 5 ) ( 1 = x x x f 5. 8 3 ) ( 3 = x x f x x x x f 192 24 509 ) ( 2 3 1 = 6. ( ) 1 log ) ( 2 + + = x x x f a 2 ) ( 1 x x a a x f = 7. 0 5 ) ( 0 3 = < x si x f x si x x 0 log ) ( 0 log 5 1 3 = < x si x x f x si x x 8. 1 10 10 10 10 ) ( + + = x x x x x f x x x f = 2 log 2 1 ) ( 2 1 2 0 < < x 9. 2 ) 1 log( ) 1 log( = + x x x x x f = 2 log 2 1 ) ( 2 1 10. Determine la posición relativa de las rectas y=3x-2 e y=-2x-2. Si se cortan halla también las coordenadas del punto de corte. Son secantes y se cortan en el punto (0,-2)
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  • Fall '09
  • NUCAMENDI
  • Calculus, Punto, Número negativo, Óscar Fuentes M

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