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Unformatted text preview: Remember that males are hemizygous for X-linked genes, and females can be homozygous or heterozygous). I1 RF 3 y II4 RF 2 y I2 RF 1 RF 2 II5 RF 1 RF 3 II1 RF 1 y II2 RF 2 y II6 RF 2 y II3 RF 2 RF 3 II7 RF 1 y b. Is there evidence for close linkage between the probe sequence and the X-linked gene for polydactyly? Explain your reasoning. Yes, there is evidence that there is close linkage because the daughters and the mothers share the same probe sequence and RF 2 is a carrier. c. How many daughters in the pedigree are likely to be carriers of X-linked polydactyly? Explain your reasoning. 1 daughter is likely to be a carrier because the first daughter has the RF 2 gene and the other daughter does not have that gene. Name _______________________ Biology 392 November 7, 2006 Quiz #3 - 10 pts...
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This note was uploaded on 04/29/2008 for the course BIO 392 taught by Professor Tomkiel during the Fall '06 term at UNC Greensboro.
- Fall '06