ECEN325SolutionforHW3

ECEN325SolutionforHW3 - ELEN 325: Electronics #3 2.31: I12...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
ELEN 325: Electronics #3 2.31: A) From the circuit above we can get: R R R R R R R R R R R R R R R R R R R R R R R R R = + = + = = + = + = = + = + = = 2 // 2 // 2 // 2 // 2 2 2 // 3 4 2 3 2 1 B) Since the “+” port is connected to ground, at node 1, we get: 1 1 I R I R V = = Î I I = 1 Since I I I I 2 1 12 = + = RI I R I R I R I R V V 2 2 2 2 12 1 2 1 = + = + = + Also: 2 2 1 I R V V = + Î I R I R = 2 2 Î I I = 2 2 Since I I I I I I 4 2 2 2 12 13 = + = + = RI I R I R I R I R V V 4 4 2 2 2 23 2 3 2 = + = + = + Î 3 2 3 V V I R + = Î RI RI = 4 3 Î I I 4 3 = I I I I I I 8 ) 4 4 ( ) ( 3 23 4 = + = + = C) R I R I V = = 1 1 R I R I V = = 2 2 2 R I R I V = = 4 3 3 I 12 I 23 Current Direction I 4 here is in the wrong direction
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
R I R I R I V = = 8 4 3 4 2.47 A) Firstly, we set V P1 =V P2 =V P3 =…V Pn =0, the output voltage that result in response to V N1 , V N2
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 04/29/2008 for the course ECEN 325 taught by Professor Silva during the Spring '08 term at Texas A&M.

Page1 / 7

ECEN325SolutionforHW3 - ELEN 325: Electronics #3 2.31: I12...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online