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ECEN325SolutionforHW3

ECEN325SolutionforHW3 - ELEN 325 Electronics#3 2.31 I12 I23...

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ELEN 325: Electronics #3 2.31: A) From the circuit above we can get: R R R R R R R R R R R R R R R R R R R R R R R R R = + = + = = + = + = = + = + = = 2 // 2 // 2 // 2 // 2 2 2 // 3 4 2 3 2 1 B) Since the “+” port is connected to ground, at node 1, we get: 1 1 I R I R V = = Î I I = 1 Since I I I I 2 1 12 = + = RI I R I R I R I R V V 2 2 2 2 12 1 2 1 = + = + = + Also: 2 2 1 I R V V = + Î I R I R = 2 2 Î I I = 2 2 Since I I I I I I 4 2 2 2 12 13 = + = + = RI I R I R I R I R V V 4 4 2 2 2 23 2 3 2 = + = + = + Î 3 2 3 V V I R + = Î RI RI = 4 3 Î I I 4 3 = I I I I I I 8 ) 4 4 ( ) ( 3 23 4 = + = + = C) R I R I V = = 1 1 R I R I V = = 2 2 2 R I R I V = = 4 3 3 I 12 I 23 Current Direction I 4 here is in the wrong direction
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